使用sql從字符串中刪除重複項

Question

如果我在表中有一個類似於'10,10,20,30,40,20'的值，那麼我想使它成爲'10,20,30,40,40 '

有沒有什麼sql函數可以做這樣的事情？

感謝 Sudhakar

Answer 1

這篇很久以前。這可能需要一些修改。但它會產生輸出。

嘗試：用傑夫的DelimitedSplit8K

DECLARE @Data_String AS VARCHAR(1000), @Result as varchar(1000)='' 
SET @Data_String = '10,10,20,30,40,20' 
SET @Data_String = REPLACE(@Data_String,'|',',') 

select @Data_String; 

SELECT @Result=@Result+col+',' from(
    SELECT DISTINCT t.c.value('.','varchar(100)') col from(
     SELECT cast('<A>'+replace(@Data_String,',','</A><A>')+'</A>' as  xml)col1)data 
    cross apply col1.nodes('/A') as t(c))Data 
SELECT LEFT(@Result,LEN(@Result)-1) 

Answer 2

從http://www.sqlservercentral.com/articles/Tally+Table/72993/

declare @value  varchar(100) = '10,10,20,30,40,20', 
    @new_value varchar(100) 

select @new_value = isnull(@new_value + ',', '') + Item 
from DelimitedSplit8K(@value, ',') 
group by Item 
order by Item 

select @new_value 

Answer 3

相信它存儲整數你可以先創建一個功能，你需要分割的數值讓他們則必須使用不同功能如下

第一個創建功能，如

CREATE FUNCTION [dbo].[idpGetSplitedString] 
(
    @String varchar(8000), 
    @Delimiter char(1) 
) 
RETURNS 
@temptable TABLE 
(
    items varchar(8000) 
) 
AS 
BEGIN 
    declare @idx int   
    declare @slice varchar(8000)   

    select @idx = 1   
     if len(@String)<1 or @String is null return   

    while @idx!= 0   
    begin   
     set @idx = charindex(@Delimiter,@String)   
     if @idx!=0   
      set @slice = left(@String,@idx - 1)   
     else   
      set @slice = @String   

     if(len(@slice)>0) 
      insert into @temptable(Items) values(rtrim(ltrim(@slice)))   

     set @String = right(@String,len(@String) - @idx)   
     if len(@String) = 0 break   
    end 

    RETURN 
END 

然後調用等

功能中選擇[DBO] .idpGetSplitedString作爲值