哪裏有不同的條件

Question

我有一個表，並希望執行以下使用where。我想選擇所有具有NUM_ORDERS = 1的行，其中CHANNEL_ID in (1,2,3,4)以及另外的所有行都是NUM_ORDERS > 1和CHANNEL_ID in (1,2,3)。我怎樣才能結合這兩個條件？

感謝您的幫助。

Answer 1

以下SQL查詢應該這樣做。請注意，由於運算符的優先級，我在where子句中使用的括號不是必需的。

SELECT * 
    FROM [put_your_table_here] 
    WHERE (NUM_ORDERS = 1 AND CHANNEL_ID IN (1,2,3,4)) OR (NUM_ORDERS > 1 AND CHANNEL_ID IN (1,2,3)) 

Answer 2

這將是這樣的：

SELECT * 
FROM tableName 
WHERE (NUM_ORDERS = 1 AND CHANNEL_ID IN (1,2,3,4)) 
OR (NUM_ORDERS > 1 AND CHANNEL_ID IN (1,2,3)) 

Answer 3

您可以使用UNION相結合的查詢＃1和＃查詢2的結果。

select * from [table] where NUM_ORDERS = 1 AND CHANNEL_ID in (1,2,3,4) 
UNION 
select * from [table] where NUM_ORDERS > 1 AND CHANNEL_ID in (1,2,3); 

UNION運算符默認情況下只選擇不同的值。要允許重複的值，使用UNION ALL：

select * from [table] where NUM_ORDERS = 1 AND CHANNEL_ID in (1,2,3,4) 
UNION ALL 
select * from [table] where NUM_ORDERS > 1 AND CHANNEL_ID in (1,2,3); 

另一種更好的解決方案是使用OR條款是這樣;

SELECT * from [table] where (NUM_ORDERS = 1 AND CHANNEL_ID in (1,2,3,4)) or (NUM_ORDERS > 1 and CHANNEL_ID in (1,2,3)); 

Answer 4

您有幾種選擇：

使用或：

SELECT... 
WHERE (NUM_ORDERS = 1 AND CHANNEL_ID in (1,2,3,4)) 
OR 
(NUM_ORDERS > 1 and CHANNEL_ID in (1,2,3)) 

另外，工會兩個：

SELECT... 
WHERE NUM_ORDERS = 1 AND CHANNEL_ID in (1,2,3,4) 
UNION 
SELECT... 
WHERE NUM_ORDERS > 1 and CHANNEL_ID in (1,2,3)