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我有類似的類Laminat和油氈爲什麼類名未找到時,我直接調用它laravel5
<?php namespace App\Http\Controllers\Parsing\Samara; class Laminat extends BaseSupply {
public $manufacture = 'Без производителя';
public $class = 'null';
public $depth = 'null';
public $collection = 'Без коллекции'; }
油氈:
<?php namespace App\Http\Controllers\Parsing\Samara; class Linoleum extends BaseSupply {
public $manufacture = 'Без производителя';
public $collection = 'Без коллекции';
public $width = 'null'; }
,我試圖用它像
$path = "App\Http\Controllers\Parsing\Samara\Linoleum";
$item = new $path();
dd($item);
如果我創建層疊的實例它與dd響應
如果我創建的油氈對此的反應實例與DD
什麼我做不好呢?
檢查文件名'Linoleum.php'和目錄,在'App \ Http \ Controllers \ Parsing \ Samara \' –
裏面我得到了一切正確的文件 - linoleum.php和Laminat.php –