如何計算球員得分與PHP

Question

我有一個JSON字符串與球員的統計數據，我想總的球員得分在這裏，玩家名稱是JSON

<code>{ 
"Players": [ 
    { 
     "playerId": 1, 
     "player_name": "Player 1", 
     "player_score": 10 
     "game_type": "action" 

    }, 
    { 
     "playerId": 2, 
     "player_name": "Player 1", 
     "player_score": 120 
     "game_type": "action" 
    }, 
    { 
     "playerId": 1, 
     "player_name": "Player 1", 
     "player_score": 233 
     "game_type": "action" 
    }, 
    { 
     "playerId": "n", 
     "player_name": "Player n", 
     "player_score": "n" 
    } 
    ] 
    } 

</code> 

的例子。在這個例子中，我需要例如找到玩家1並計算所有點數 所以這就是它應該是正確的玩家1有233點+10點= 243點，$ player_name => $ totalpoints;

我試着用循環來做到這一點，但沒有成功。

Answer 1

循環遍歷數組，然後將它們添加..讓我假設數組名是$players的話..

$total_score = 0; 
foreach($players as $key=>$value) 
{ 
    if($value['player_name']=='player1') 
    { 
    $total_score +=$value['player_score']; 
    } 
} 
echo "PLAYER's TOTAL SCORE = ".$total_score; 

編輯：

這看起來像JSON代碼..所以首先對其進行解碼使用json_decode

Answer 2

下面是一個辦法做到這一點：

//Convert json to php array 
$listPlayers = json_decode({ 
"Players": [ 
    { 
     "playerId": 1, 
     "player_name": "Player 1", 
     "player_score": 10 
    }, 
    { 
     "playerId": 2, 
     "player_name": "Player 1", 
     "player_score": 120 
    }, 
    { 
     "playerId": 1, 
     "player_name": "Player 1", 
     "player_score": 233 
    }, 
    { 
     "playerId": "n", 
     "player_name": "Player n", 
     "player_score": "n" 
    } 
    ] 
    }); 

//Sum score for each player id 
$totalByPlayers = array(); 
foreach($listPlayers as $player) 
{ 
    //If player doesnt exists yet, we create it 
    if(false === isset($totalByPlayers[$player['playerId']])) 
    { 
     $totalByPlayers[$player['playerId']] = 0; 
    } 

    $totalByPlayers[$player['playerId']] += $player['player_score']; 
} 

//Then for score of player one : 
echo $totalByPlayers[1]; 

Answer 3

這應該適合你！ 修訂

乾杯馬里奧

$json = '[{"playerId": 1,"player_name": "Player 1","player_score": 10}, {"playerId": 2,"player_name": "Player 1","player_score": 20},{"playerId": 1,"player_name": "Player 1","player_score": 233},{"playerId": "3","player_name": "Player 3","player_score": "3"}]'; 
$array = json_decode($json, true); 
$totalcount = array(); 
foreach ($array as $key => $value){ 
    if (!empty($totalcount[$value['playerId']])) { 
     $totalcount[$value['playerId']] += $value['player_score']; 
    } 
    else 
    { 
    array_push($totalcount, $value['playerId'],$value['player_score']); 
    } 
} 
foreach ($totalcount as $key => $value) { 
echo "Player ".$key." total=".$value."<br>"; 
} 

Answer 4

試試這個。通過使用這個，你可以得到你想要的結果。

$player_array = json_decode($json_string); // put your json string variable 

$palyer_array_total = array(); 
foreach($player_array as $player){ 
     $palyer_array_total[$player['playerId']]['name'] = $player['player_name']; 
     if(isset($palyer_array_total[$player['playerId']]['total_score'])){ 
      $palyer_array_total[$player['playerId']]['total_score'] = $palyer_array_total[$player['playerId']]['total_score']+$player['player_score']; 
     }else{ 
      $palyer_array_total[$player['playerId']]['total_score'] = $player['player_score']; 
     } 
} 
echo "<pre>"; print_r($palyer_array_total);