PHP語法eroor

Question

解析錯誤：語法錯誤，意外 '$用戶'（T_VARIABLE）在C：\ XAMPP \ htdocs中\ 4號線

<?php 

$host = "localhost" 
$user = "root"; <------ line 4 
$pass = ""; 
$db = "table"; 

mysql_connect($host, $user, $pass); 
mysql_select_db($db); 

if (isset($_POST['username'])) { 
    $username = $_POST['username']; 
    $password = $_POST['password']; 

    $sql = "SELECT * FROM users WHERE username='$username' AND password='$password'"; 
    $res = mysql_query($sql); 

    if (mysql_num_rows($res) == 1) { 
     echo "Super"; 
     exit(); 
    } else { 
     echo "Siper"; 
     exit(); 
    } 
} 

?> 

家\ login.php中如何解決呢？

Answer 1

你錯過了第一行分號。請記住，在php中，錯誤通常指的是左右的行號，並且不一定是上的行。 :)

即

$host = "localhost"; 

編輯：

您可能還需要淨化你的$ _ POST數據，或重新考慮你構建這樣的方式，否則你要離開的事打開SQL注入。

採取通過這裏瞭解更多信息，請閱讀： What's the best method for sanitizing user input with PHP?

Answer 2

缺少分號：

<?php 

$host = "localhost"; <--- error :D 
$user = "root"; <------ line 4 
$pass = ""; 
$db = "table"; 

mysql_connect($host, $user, $pass); 
mysql_select_db($db); 

if (isset($_POST['username'])) { 
    $username = $_POST['username']; 
    $password = $_POST['password']; 

    $sql = "SELECT * FROM users WHERE username='$username' AND password='$password'"; 
    $res = mysql_query($sql); 

    if (mysql_num_rows($res) == 1) { 
     echo "Super"; 
     exit(); 
    } else { 
     echo "Siper"; 
     exit(); 
    } 
} 

?>