2011-12-26 61 views
0

我有此JSONMySql的環路JSON

{ 
     "category": [ 
      { 
        "catname": "gallery1", 
        "imageCar": "www.blabla.com/jpeg", 
        "content": [ 
         { 
           "name": "Loas Angeles", 
           "address": "Seatle Street", 
           "lat": -7.6090925, 
           "lng": 110.209893, 
           "imageUrl": "http://files.wordpress.com/2010/10/b21.jpg", 
           "gallery": [ 
            { 
              "galleryUrl": "http:/00/inboro02.jpg" 
            }, 
            { 
              "galleryUrl": "hddfd.jpg" 
            }, 
            { 
              "galleryUrl": "http://1.bsf2B3.jpg" 
            } 
           ] 
         } 
        ] 
      } 
     ] 
} 

如何SQL語法或PHP代碼?

+0

你的問題並不十分清楚。你在問什麼? – 2011-12-26 11:49:36

+1

但有人已經不得不對它投票。有時候我不明白人們腦子裏會發生什麼。 – 2011-12-26 11:50:13

回答

0

使用

$decoded = json_decode($yourJsonData);