這裏是一個企圖得到關於電子< <和>>流運營商自動只有一行宏命令NUM ...
定義：
#include <string>
#include <iostream>
#include <stdexcept>
#include <algorithm>
#include <iterator>
#include <sstream>
#include <vector>
#define MAKE_STRING(str, ...) #str, MAKE_STRING1_(__VA_ARGS__)
#define MAKE_STRING1_(str, ...) #str, MAKE_STRING2_(__VA_ARGS__)
#define MAKE_STRING2_(str, ...) #str, MAKE_STRING3_(__VA_ARGS__)
#define MAKE_STRING3_(str, ...) #str, MAKE_STRING4_(__VA_ARGS__)
#define MAKE_STRING4_(str, ...) #str, MAKE_STRING5_(__VA_ARGS__)
#define MAKE_STRING5_(str, ...) #str, MAKE_STRING6_(__VA_ARGS__)
#define MAKE_STRING6_(str, ...) #str, MAKE_STRING7_(__VA_ARGS__)
#define MAKE_STRING7_(str, ...) #str, MAKE_STRING8_(__VA_ARGS__)
#define MAKE_STRING8_(str, ...) #str, MAKE_STRING9_(__VA_ARGS__)
#define MAKE_STRING9_(str, ...) #str, MAKE_STRING10_(__VA_ARGS__)
#define MAKE_STRING10_(str) #str
#define MAKE_ENUM(name, ...) MAKE_ENUM_(, name, __VA_ARGS__)
#define MAKE_CLASS_ENUM(name, ...) MAKE_ENUM_(friend, name, __VA_ARGS__)
#define MAKE_ENUM_(attribute, name, ...) name { __VA_ARGS__ }; \
attribute std::istream& operator>>(std::istream& is, name& e) { \
const char* name##Str[] = { MAKE_STRING(__VA_ARGS__) }; \
std::string str; \
std::istream& r = is >> str; \
const size_t len = sizeof(name##Str)/sizeof(name##Str[0]); \
const std::vector<std::string> enumStr(name##Str, name##Str + len); \
const std::vector<std::string>::const_iterator it = std::find(enumStr.begin(), enumStr.end(), str); \
if (it != enumStr.end())\
e = name(it - enumStr.begin()); \
else \
throw std::runtime_error("Value \"" + str + "\" is not part of enum "#name); \
return r; \
}; \
attribute std::ostream& operator<<(std::ostream& os, const name& e) { \
const char* name##Str[] = { MAKE_STRING(__VA_ARGS__) }; \
return (os << name##Str[e]); \
}
用法：
// Declare global enum
enum MAKE_ENUM(Test3, Item13, Item23, Item33, Itdsdgem43);
class Essai {
public:
// Declare enum inside class
enum MAKE_CLASS_ENUM(Test, Item1, Item2, Item3, Itdsdgem4);
};
int main() {
std::cout << Essai::Item1 << std::endl;
Essai::Test ddd = Essai::Item1;
std::cout << ddd << std::endl;
std::istringstream strm("Item2");
strm >> ddd;
std::cout << (int) ddd << std::endl;
std::cout << ddd << std::endl;
}
不知道這個方案的侷限性，但...評論，歡迎！
可能的重複[簡單的方法來使用枚舉類型的變量作爲C中的字符串？]（http://stackoverflow.com/questions/147267/easy-way-to-use-variables-of-enum-types- as-string-in-c） – karlphillip 2011-07-02 23:26:52
關於基於宏的工廠移動到http://stackoverflow.com/questions/147267/easy-way-to-use-variables-of-enum-types-as-string-in- c＃202511 - 問題更新後，它在這裏不再相關。 – Suma 2008-10-14 15:42:21