將字符串轉換爲沒有CGo的C字符串

Question

我試圖從Go中調用一些ioctl，其中一些字符串以C字符串作爲參數。例如，在C：

/* When the user asks to bind a message name to an interface, they use: */ 
struct kbus_bind_request { 
    __u32 is_replier; /* are we a replier? */ 
    __u32 name_len; 
    char *name; 
}; 

extern int kbus_ksock_bind(kbus_ksock_t   ksock, 
          const char   *name, 
          uint32_t    is_replier) 
{ 
    int rv; 
    kbus_bind_request_t bind_request; 

    bind_request.name = (char *) name; 
    bind_request.name_len = strlen(name); 
    bind_request.is_replier = is_replier; 

    rv = ioctl(ksock, KBUS_IOC_BIND, &bind_request); 
    if (rv < 0) 
    return -errno; 
    else 
    return rv; 
} 

我轉換結構將轉至STRUC這樣的：

type kbus_bind_request struct { 
    is_replier uint32 /* are we a replier? */ 
    name_len uint32 
    name  unsafe.Pointer // char* 
} 

現在，我怎麼轉換轉到string存儲在一個unsafe.Pointer C字符串？我不想使用CGo，因爲我正在交叉編譯，這讓事情變得很痛苦。

Answer 1

啊找到了答案（以及編譯的東西）。首先投給[]byte，然後在第一個元素的地址：

func int_bind(ksock int, name string, is_replier uint32) int { 

    bind_request := &kbus_bind_request{} 

    s := []byte(name) 

    bind_request.name = unsafe.Pointer(&s[0]) 
    bind_request.name_len = uint32(len(s)) 
    bind_request.is_replier = is_replier 

    rv := ioctl(ksock, KBUS_IOC_BIND, unsafe.Pointer(bind_request)) 

    if rv != 0 { 
     return -int(rv) 
    } 
    return 0 
}