爲了作業目的,我編寫了下面的代碼。當我在OSX中的XCode上運行它時,在輸入「輸入斐波那契數列:」的句子後,我輸入數字2次。爲什麼2和只有1 scanf
。在子進程中使用fork()的斐波那契
代碼:
#include <stdio.h>
#include <sys/types.h>
#include <unistd.h>
#include <sys/wait.h>
int main()
{
int a=0, b=1, n=a+b,i;
printf("Enter the number of a Fibonacci Sequence:\n");
scanf("%d ", &i);
pid_t pid = fork();
if (pid == 0)
{
printf("Child is make the Fibonacci\n");
printf("0 %d ",n);
while (i>0) {
n=a+b;
printf("%d ", n);
a=b;
b=n;
i--;
if (i == 0) {
printf("\nChild ends\n");
}
}
}
else
{
printf("Parent is waiting for child to complete...\n");
waitpid(pid, NULL, 0);
printf("Parent ends\n");
}
return 0;
}