2017-09-13 91 views
0

我有一個父組件控制所有狀態和一個子組件,它返回一個下拉菜單並傳遞(應該傳遞,而不是)點擊一個選項的結果,直到父組件,並更新父母的狀態。反應下拉不設置狀態

家長:

// We're controlling all of our state here and using children 
// components only to return lists and handle AJAX calls. 

import React, { Component } from 'react'; 
import SubList from './SubList'; 
import StopList from './StopList'; 

class SubCheck extends Component { 

    constructor (props) { 
    super(props); 
    this.state = { 
     selectedSub: null, 
     selectedStop: null, 
     stops: [], 
    }; 
    this.handleSubSelect.bind(this); 
    this.handleStopSelect.bind(this); 
    } 

    // We want the user to be able to select their specific subway 
    // stop, so obviously a different array of stops needs to be 
    // loaded for each subway. We're getting those from utils/stops.json. 
    handleSubSelect(event) { 
     var stopData = require('../utils/stops'); 
     var stopsArray = []; 
     for (var i = 0; i < stopData.length; i++) { 
      var stop = stopData[i]; 

      if (stop.stop_id.charAt(0) == event.target.onSubSelect) { 
       stopsArray.push(stop.stop_name); 
      } 
     } 
     this.setState(() => { 
      console.log('setting state'); 
      return { 
       selectedSub: event.target.onSubSelect, 
       stops: stopsArray 
      } 
     }); 
    } 

    handleStopSelect(event) { 
     this.setState({selectedStop: event.target.onStopSelect}); 
    } 

    render() { 
     return (
      <div> 
       <SubList onSubSelect={this.handleSubSelect.bind(this)}/> 
       <StopList stops={this.state.stops} onStopSelect={this.handleStopSelect.bind(this)}/> 
      </div> 
     ); 
    } 
} 

export default SubCheck; 

兒童:

import React from 'react'; 
import PropTypes from 'prop-types'; 

function SubList (props) { 
    const subways = ['', '1', '2', '3', '4', '5', '6', 
    'S', 'C', 'B', 'D', 'N', 'Q', 'R', 'L'] 
    return (
     <select> 
      { 
       subways.map(subway => 
        <option key={subway} onClick={() => props.onSubSelect(subway)}> 
         {subway} 
        </option> 
       ) 
      } 
     </select> 
    ) 
} 
SubList.PropTypes = { 
    onSubSelect: React.PropTypes.func.isRequired 
}; 

export default SubList; 

當我打開應用程序的是,選擇從下拉菜單中的選項,兩件事情不會發生,我會希望發生。一個是第二個菜單(由Stop​​List返回的,其代碼未包含在此)沒有填充任何數據。第二件事是'設置狀態'沒有記錄到控制檯。第二件事是讓我相信在我的代碼的某個地方,我沒有正確地將下拉選項中的選項傳遞給我的handleSubSelect方法,因此沒有正確設置任何新的狀態。

+0

哪裏是'StopList'的代碼?它究竟做了什麼? – Dekel

回答

0

你已經做了綁定,所以你並不需要的是,在當用戶更改選擇其實你正在做的是做綁定

因此改變這一行做

<SubList onSubSelect={this.handleSubSelect.bind(this)}/> 

到這

<SubList onSubSelect={this.handleSubSelect}/> 

和世界應該更快樂。

您有onStopSelect

UPDATE

handleSubSelect()方法你做到這一點

同樣的問題:

this.setState(() => { 
     console.log('setting state'); 
     return { 
      selectedSub: event.target.onSubSelect, 
      stops: stopsArray 
     } 
    }); 

這看起來有點搞砸了,我想應該是這樣:

console.log('setting state'); 
    this.setState({ 
      selectedSub: event.target.onSubSelect, 
      stops: stopsArray 
     } 
    ); 
+0

試過但沒有變化:( – bkula

+0

更新後仍然沒有變化 – bkula

0

你應該結合方法爲:

this.handleStopSelect = this.handleStopSelect.bind(this); 

here。當然,改變的元素如下所示:

<SubList onSubSelect={this.handleSubSelect}/> 

而且代替event.target.onSubSelect 你可以嘗試event.target.value

+0

嘗試了所有這一切,沒有改變我的輸出 – bkula