2
time_t now = time(0);
std::string h = std::string (ctime (&now));
std::cout << "\nh: " << h;
,我接收電流輸出爲:Thu Sep 14 10:58:26 2017
如何用time_t更改日期和時間的格式?
我想要的輸出2017-08-26-16-10-56
我能做些什麼來該輸出?
time_t now = time(0);
std::string h = std::string (ctime (&now));
std::cout << "\nh: " << h;
,我接收電流輸出爲:Thu Sep 14 10:58:26 2017
如何用time_t更改日期和時間的格式?
我想要的輸出2017-08-26-16-10-56
我能做些什麼來該輸出?
使用strftime,像這樣:
strftime (buffer, 80,"%Y-%m-%d-%H-%M-%S",timeinfo);
全碼:
#include <cstdio>
#include <ctime>
int main()
{
time_t rawtime;
struct tm * timeinfo;
char buffer [80];
time (&rawtime);
timeinfo = localtime (&rawtime);
strftime (buffer, 80,"%Y-%m-%d-%H-%M-%S",timeinfo);
puts (buffer);
return 0;
}
輸出:
2017-09-14-14-41-19
#include <iomanip>
time_t now = time(0);
std::string h = std::put_time(localtime(&now), "%F-%H-%M-%S");
std::cout << "\nh: " << h;
輸出
H:2017-09-14-05-54-02
更妙的是,使用std::chrono
#include <iostream>
#include <iomanip>
#include <chrono>
using namespace std;
int main() {
auto now = chrono::system_clock::to_time_t(chrono::system_clock::now());
cout << put_time(localtime(&now), "%F-%H-%M-%S") << endl;
return 0;
}
相關問題:https://stackoverflow.c OM /問題/ 3673226 /如何對打印時的格式,2009-08-10-181754-811 – rsp