用單個空格替換字符串中的多空格 - Python

Question

循環字符串並用單個空格替換雙空格的開銷會花費太多時間。嘗試用單個空白替換字符串中的多個間距是否更快？

我已經做了這樣的，但它只是時間太長，浪費的：

str1 = "This is a foo bar sentence with crazy spaces that irritates my program " 

def despace(sentence): 
    while " " in sentence: 
    sentence = sentence.replace(" "," ") 
    return sentence 

print despace(str1) 

Answer 1

看看這個

In [1]: str1 = "This is a foo bar sentence with crazy spaces that irritates my program " 

In [2]: ' '.join(str1.split()) 
Out[2]: 'This is a foo bar sentence with crazy spaces that irritates my program' 

split()返回的所有單詞列表中的方法該字符串，使用str作爲分隔符（如果未指定，則在所有空白處分割）

Answer 2

使用regular expressions：

import re 
str1 = re.sub(' +', ' ', str1) 

' +'匹配一個或多個空格字符。

您還可以

str1 = re.sub('\s+', ' ', str1) 

更換空白的所有運行