如何只導入滿足條件的行？

Question

我的查詢是：

SELECT 
    t.* 
FROM 
    (SELECT 
     ig_idx, 
     --, count(ig_root) over(partition by ig_root) AS GameCount1 
     ig_root, 
     ig_game_type, 
     ROW_NUMBER() OVER (PARTITION BY ig_root 
          ORDER BY CASE WHEN ig_game_type IN ('12', '1x2') THEN 0 ELSE 1 END, ig_game_type ASC) AS seqnum 
    FROM 
     Info_Game) AS t 
ORDER BY 
    ig_root, seqnum 

結果：

SQL Fiddle

的SQL Server 2014表架構

CREATE TABLE Info_Game 
(
    [ig_idx] int, 
    [GameCount1] int, 
    [ig_root] int, 
    [ig_game_type] varchar(5), 
    [old_seqnum] int 
); 

INSERT INTO Info_Game ([ig_idx], [GameCount1], [ig_root], [ig_game_type], [old_seqnum]) 
VALUES (1, 3, 11, '12', 1), 
     (2, 3, 11, 'ah', 2), 
     (3, 3, 11, 'ou', 3), 
     (4, 1, 12, '12', 1), 
     (5, 4, 13, '1h_ah', 1), 
     (6, 4, 13, '2h_ou', 2), 
     (7, 4, 13, 'ah', 3), 
     (8, 4, 13, 'ou', 4), 
     (9, 4, 13, '1h_ou', 5), 
     (10, 5, 14, '1x2', 1), 
     (11, 5, 14, '1h_ah', 2), 
     (12, 5, 14, 'h', 3), 
     (13, 5, 14, 'ou', 4), 
     (14, 5, 14, '1h_ou', 5); 

只有ig_root與1 SEQNUM和 '12' 或'的ig_game_type 1x2'。

我想獲得相同數量的

我想要的結果

SQL Fiddle

的SQL Server 2014架構

CREATE TABLE Info_Game 
(
    [ig_idx] int, 
    [GameCount1] int, 
    [ig_root] int, 
    [ig_game_type] varchar(5), 
    [old_seqnum] int 
); 

INSERT INTO Info_Game ([ig_idx], [GameCount1], [ig_root], [ig_game_type], [old_seqnum]) 
VALUES (1, 3, 11, '12', 1), 
     (2, 3, 11, 'ah', 2), 
     (3, 3, 11, 'ou', 3), 
     (4, 1, 12, '12', 1), 
     (10, 5, 14, '1x2', 1), 
     (11, 5, 14, '1h_ah', 2), 
     (12, 5, 14, 'h', 3), 
     (13, 5, 14, 'ou', 4), 
     (14, 5, 14, '1h_ou', 5); 

相同數量ig_root的的ig_root，SEQNUM = 1和type ='12'或type ='1x2' 我想要得到它相同數的ig_root

ig_idx ig_root ig_game_type seqnum 
1  11  12   1 
2  11  ah   2 
3  11  ou   3 
4  12  12   1 
5  13  1h_ah   1 <--- this 
9  13  1h_ou   2 
6  13  2h_ou   3 
7  13  ah   4 
8  13  ou   5 
10  14  1x2   1 
11  14  1h_ah   2 
14  14  1h_ou   3 
12  14  h    4 
13  14  ou   5 

idx 5：這意味着seqnum是1, ，但類型不是12或1x2。 所以我不希望把ig_root 13號

這樣的：

ig_idx ig_root ig_game_type seqnum 
1  11  12   1 
2  11  ah   2 
3  11  ou   3 
4  12  12   1 
10  14  1x2   1 
11  14  1h_ah   2 
14  14  1h_ou   3 
12  14  h    4 
13  14  ou   5 

Answer 1

with cte as (
     SELECT 
      * 
      , ROW_NUMBER() OVER (PARTITION BY ig_root ORDER BY ig_idx) AS seqnum 
     FROM Info_Game 
) 
select ig1.* 
from Info_Game ig1 
where exists (
     select * 
     from cte ig2 
     where ig2.ig_root = ig1.ig_root 
      and ig2.ig_game_type in ('12', '1x2') 
      and ig2.seqnum = 1 
    ) 

這將返回從Info_Game所有行的其中一個行存在同時具有「12」或「1×2」的ig_game_type，是第一排具有相同ig_root值的所有行。對於我來說，'第一'的定義並不清楚，所以我冒昧地使用ig_idx來進行排序。 SQLFiddle

Answer 2

如果您只想輸出（或保留）其中的一些行，然後用低於WHERE clause如一個：

 
SELECT 
     t.* 
FROM (
     SELECT 
      ig_idx 
      --, count(ig_root) over(partition by ig_root) AS GameCount1 
      , ig_root 
      , ig_game_type 
      , ROW_NUMBER() OVER (PARTITION BY ig_root 
           ORDER BY CASE WHEN ig_game_type IN ('12', '1x2') THEN 0 ELSE 1 END 
           , ig_game_type ASC 
          ) AS seqnum 
     FROM Info_Game 
    ) AS t 
WHERE t.seqnum in (1,2) 
ORDER BY ig_root, seqnum 
; 

只有ig_root具有1 SEQNUM和ig_game_type '12' 或 '1×2' 的

由於我不明白，這完全是爲WHERE clause一些替代：

 
WHERE t.seqnum = 1 

WHERE ig_game_type n('12','1x2') 

我希望這有助於。

Answer 3

難以解碼您的問題，但從我udnerstand，你想從你發佈的查詢中得到幾行。因此，簡單地用where條款即WHERE ig_game_type in('12','1x2') and seqnum = 1這樣的：

SELECT 
     t.* 
FROM (
     SELECT 
      ig_idx 
      --, count(ig_root) over(partition by ig_root) AS GameCount1 
      , ig_root 
      , ig_game_type 
      , ROW_NUMBER() OVER (PARTITION BY ig_root 
           ORDER BY CASE WHEN ig_game_type IN ('12', '1x2') THEN 0 ELSE 1 END 
           , ig_game_type ASC 
          ) AS seqnum 
     FROM #Info_Game 
    ) AS t 
WHERE ig_game_type in('12','1x2') and seqnum = 1 
ORDER BY ig_root, seqnum