錯誤：org.hibernate.exception.SQLGrammarException：無法提取ResultSet和dateAccessed不詳列

Question

我在春天執行下面的查詢MVC JAVA

if (currentFireTime != null && previousFireTime != null) { 
     timePart = " sal.dateAccessed between '" + previousFireTime + "' and '" + currentFireTime + "' and "; 
    } 
    String queryString = " select count(*) as COUNT FROM LogData sal where " + timePart + " sal.userSigned = false and sal.batchMetaDataId = "+batchId; 
    SQLQuery sq =sessionFactory.getCurrentSession().createSQLQuery(queryString); 
    sq.addScalar("COUNT", IntegerType.INSTANCE); 
    sq.setResultTransformer(AliasToEntityMapResultTransformer.INSTANCE); 
    List<Map<String,Object>> resultSet=sq.list(); 
    return (Integer)resultSet.get(0).get("COUNT"); 

當執行這個樣子的，並把這種在MySQL它的工作原理精細。但是我得到如下所示的錯誤。顯示

select count(*) as COUNT FROM LogData sal where sal.dateAccessed between '2016-12-26 00:00:00.618' and '2016-12-26 01:00:00.618' and sal.userSigned = false and sal.batchMetaDataId = 86 

錯誤

org.hibernate.exception.SQLGrammarException: could not extract ResultSet 
at org.hibernate.exception.internal.SQLExceptionTypeDelegate.convert(SQLExceptionTypeDelegate.java:82) 
at org.hibernate.exception.internal.StandardSQLExceptionConverter.convert(StandardSQLExceptionConverter.java:49) 
at org.hibernate.engine.jdbc.spi.SqlExceptionHelper.convert(SqlExceptionHelper.java:125) 
at org.hibernate.engine.jdbc.spi.SqlExceptionHelper.convert(SqlExceptionHelper.java:110) 

我應該需要什麼所示的代碼改變？

Answer 1

您正在以錯誤的方式提取計數。試試這個：

resultSet.getInt("COUNT");