連續計數非空值

Question

有沒有更好的方法來做到這一點？

select count(First)+count(id)+count(Last)+count(Telephone) 
from client 
where id ="1"; 

Answer 1

不知道這是更好，但目的可能更清楚後來有人讀它：

select 
    (case when First is null then 1 else 0 end) + 
    (case when id is null then 1 else 0 end) + 
    (case when Last is null then 1 else 0 end) + 
    (case when Telephone is null then 1 else 0 end) 
from client 
where id ="1";