如何設置參數化構造函數值

Question

我想將參數化構造函數值（aName和aValue）設置爲attribName和attribValue設置方法，請協助。

public class PlayerRow 
{ 
    public PlayerRow(string aName, string aValue) 
    { 
     AttribsPlayerLine = new List<AttribLine>(); 
    } 
    public List<AttribLine> AttribsPlayerLine { get; set; } 

    public class AttribLine 
    { 

    [Description("AttribName")] 
    public string attribName { get; set; } 

    [Description("AttribValue")] 
    public string attribValue { get; set; } 
    } 
} 

Answer 1

如果你能澄清我們可以提供更好的幫助，這有點讓你困惑。但如果我理解正確，這裏是我的答案，如果不是，請評論，我會編輯我的答案。

public class PlayerRow 
{ 
    public PlayerRow(string aName, string aValue) 
    { 
     AttribsPlayerLine = new List<AttribLine>(); 

     AttribLine temp = new AttribLine(); 
     temp.attribName = aName; 
     temp.attribValue = aValue; 
     AttribsPlayerLine.Add(temp); 
    } 
    public List<AttribLine> AttribsPlayerLine { get; set; } 

    public class AttribLine 
    { 

    [Description("AttribName")] 
    public string attribName { get; set; } 

    [Description("AttribValue")] 
    public string attribValue { get; set; } 
    } 
} 

但我真的沒有看到任何好處，因爲構造函數將只添加1個項目到列表中。儘管如此，你仍然可以在你的main中訪問PlayerRow對象，然後訪問AttribsPlayerLine，然後向它添加一個新的AttribLine。但對我們來說還不清楚。