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嗯，我有這個發送空白電子郵件的聯繫表。但是我做了一些測試，並且不會發生在我身上。我認爲，唯一可能發生的情況是直接訪問.php文件。如果不是，我不知道可能是什麼問題。該表格不允許您發送空白電子郵件。如果這種情況繼續發生，我會在php文件中添加一個驗證，但是直到我發現問題出在什麼地方，我不想忽略這些消息。Ajax/php聯繫表不時發送空白郵件
這是HTML
<form name="contactForm" id="contactForm" method="post" action="/contactEngine.php" onsubmit="return validateForm()">
<input title="Input name" type="text" name="Name" id="Name" placeholder="Nombre:" required="">
<input title="Input email" placeholder="Email:" type="email" name="Email" id="Email" required="">
<input type="text" placeholder="Subject:" name="Subjet" id="Subjet">
<textarea title="Input message" placeholder="Mensaje:" name="Message" rows="20" cols="20" id="Message" required=""></textarea>
<input title="Input result" placeholder="25 + 25 = ?" type="text" name="Captcha" id="Captcha" required="">
<p id="wrongCaptcha"> Try again </p>
<input type="submit" name="submit" value="send" class="submit-button">
</form>
這是JS
function validateForm(e) {
e.preventDefault();
var x = document.forms["contactForm"]["Captcha"].value;
if (x != 50) {//if captcha is wrong
$("#Captcha").addClass("wrongCaptchaEntered");
$("#Captcha").css("animation-name" , "none");
setTimeout (function(){
$("#Captcha").css("animation-name" , "changeBorder");
},100);
if ($("#wrongCaptcha").css("display") == "none"){
$("#wrongCaptcha").slideDown();
}
}
else { //if captcha is correct
var formAction = $("#contactForm").attr("action");
if (formAction == "/contactEngine.php"){
var formData = $("#contactForm").serialize();
$.post(formAction, formData, function(data){
console.log (data);
$(".formulario").changeTo({content: "<h2 class='section-title BackgroundGradientBlack'>"+ data +"</h2>"});
});
}
}
return false;
}
而且PHP
<?php
$EmailFrom = "[email protected]";
$EmailTo = "[email protected]";
$Name = Trim(stripslashes($_POST['Name']));
$Email = Trim(stripslashes($_POST['Email']));
$Subject = Trim(stripslashes($_POST['Subjet']));
$Message = Trim(stripslashes($_POST['Message']));
$email_content = "Frontpage";
$email_content .= "\nNombre: $Name";
$email_content .= "\nEmail: $Email";
$email_content .= "\nMotivo: $Subject";
$email_content .= "\nMensaje: $Message";
$email_headers = "From: <$EmailFrom>";
if (mail($EmailTo, $Subject, $email_content, $email_headers)) {
http_response_code(200);
echo "Mensaje enviado";
} else {
http_response_code(500);
echo "Error";
}
?>
謝謝！