Laravel從關係中獲取數據並在視圖中顯示

簡單地說，這段代碼就是我的獲取數據解決方案，這個模型是關係，我的結果是真實的，但是我無法從關係中獲取數據並顯示在視圖上，Laravel從關係中獲取數據並在視圖中顯示

$data = UserAccountNumber::with(['currency_type'])->orderBy('id', 'DESC')->paginate(50);

以下結果這個代碼回報：

LengthAwarePaginator {#585 ▼ 
    #total: 2 
    #lastPage: 1 
    #items: Collection {#601 ▼ 
    #items: array:2 [▼ 
     0 => UserAccountNumber {#588 ▶} 
     1 => UserAccountNumber {#589 ▼ 
     #table: "user_account_numbers" 
     #guarded: array:1 [▶] 
     #connection: null 
     #primaryKey: "id" 
     #perPage: 15 
     +incrementing: true 
     +timestamps: true 
     #attributes: array:9 [▼ 
      "id" => 2 
      "user_id" => 17 
      "account_number" => "24234234" 
      "card_number" => "242423423" 
      "sheba" => "asdasdad" 
      "currency_type" => 5 
      "status" => 0 
      "created_at" => "2016-05-13 10:55:00" 
      "updated_at" => "2016-05-13 10:55:00" 
     ] 
     #original: array:9 [▶] 
     #relations: array:1 [▼ 
      "currency_type" => CurrencyType {#603 ▼ 
      #table: "currency_type" 
      #fillable: array:3 [▶] 
      #dates: array:1 [▶] 
      #connection: null 
      #primaryKey: "id" 
      #perPage: 15 
      +incrementing: true 
      +timestamps: true 
      #attributes: array:7 [▼ 
       "id" => 5 
       "user_id" => 1 
       "currency_type" => "EURO" 
       "currency_symbol" => "EUR" 
       "created_at" => "2016-04-17 12:07:47" 
       "updated_at" => "2016-04-17 12:07:47" 
       "deleted_at" => null 
      ]

查看：

鑑於我能得到UserAccountNumber數據，但我不能讓currency_type，並表明對視圖：

<table class='table-style' cellpadding='0' cellspacing='0'> 
    @foreach ($data as $key=>$contents) 
     <tr> 
      <td>{{$contents->card_number}}</td> 
      <td>{{$contents->card_number}}</td> 
      <td>{{$contents->seba}}</td> 
      <td>{{$contents->created_at}}</td> 
      <td> 
       {{$contents->currency_type->currency_type}} 
      </td> 
     </tr> 
    @endforeach 
</table>

我得到錯誤{{$contents->currency_type->currency_type}}在視圖上。

錯誤：

Trying to get property of non-object

更新的Post：

class UserAccountNumber extends Model 
{ 
    protected $table = 'user_account_numbers'; 
    protected $guarded = ['id']; 

    public function user() 
    { 
     return $this->belongsTo('App\Http\Models\User'); 
    } 

    public function currency_type() 
    { 
     return $this->belongsTo('App\Http\Models\CurrencyType', 'currency_type', 'id'); 
    } 
}

來源

2016-05-13 Mahdi.Pishguy

燦你向我們展示你的'UserAccountNumber'模型？ – codedge

@codedge是先生。發佈更新。 –

我仍然無法看到任何'類UserAccountNumber'模型類.. – codedge

改善的第一件事是在你的UserAccountNumber模型。你currency_type關係應該這樣寫：

public function currencyType() 
{ 
    return $this->belongsTo(CurrencyType::class, 'currency_type', 'id'); 
}

那麼您的通話將如下所示：

// using the currencyType() method from above 
$data = UserAccountNumber::with('currencyType') 
    ->orderBy('id', 'DESC') 
    ->paginate(50);

然後，您可以在您使用訪問貨幣類型有：

@foreach ($data as $key=>$contents) 
    $contents->currencyType->currency_type 
@endforeach

來源

2016-05-13 14:39:22 codedge

似乎有些UserAccountNumber不具備currency_type連接到它。加入這樣的事情代碼：

@if (isset($contents->currency_type)) 
    {{ $contents->currency_type->currency_type }} 
@endif

或者：

{{ $contents->currency_type->currency_type or 'There is not type' }}

來源

2016-05-13 13:51:48

'currency_type'是一種關係 –

但是，如果有一個適當的關係，我。即一對多，一個CurrencyType-to-many-UserAccountNumbers，應該總是有一個CurrencyType，正確的@Alexey？ – codedge

Laravel從關係中獲取數據並在視圖中顯示

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