去，我想使一個結構的二維數組，但我得到一個錯誤

Question

這裏是我的代碼：

type Square struct { 
    num int //Holds the number. 0 is empty 
} 

func somefunc() { 
    squares := [4][4]Square 

但我得到這個錯誤：

type [4][4]Square is not an expression 

Answer 1

使用squares := [4][4]Square{}完成複合文字，或使用var squares [4][4]Square來聲明變量。

Answer 2

2D陣列和初始化：

package main 

import (
    "fmt" 
) 

type Square struct { 
    num int //Holds the number. 0 is empty 
} 

func main() { 
    squares0 := [4][4]Square{} // init to zeros 
    fmt.Println(squares0) 

    var squares [4][4]Square // init to zeros 
    fmt.Println(squares) 

    squares2 := [4][4]Square{{}, {}, {}, {}} // init to zeros 
    fmt.Println(squares2) 

    squares3 := [4][4]Square{ 
     {{1}, {2}, {3}, {4}}, 
     {{5}, {6}, {7}, {8}}, 
     {{9}, {10}, {11}, {12}}, 
     {{13}, {14}, {15}, {16}}} 
    fmt.Println(squares3) 

    for i := 0; i < 4; i++ { 
     for j := 0; j < 4; j++ { 
      squares[i][j].num = (i+1)*10 + j + 1 
     } 
    } 
    fmt.Println(squares) 
} 

輸出：

[[{0} {0} {0} {0}] [{0} {0} {0} {0}] [{0} {0} {0} {0}] [{0} {0} {0} {0}]] 
[[{0} {0} {0} {0}] [{0} {0} {0} {0}] [{0} {0} {0} {0}] [{0} {0} {0} {0}]] 
[[{0} {0} {0} {0}] [{0} {0} {0} {0}] [{0} {0} {0} {0}] [{0} {0} {0} {0}]] 
[[{1} {2} {3} {4}] [{5} {6} {7} {8}] [{9} {10} {11} {12}] [{13} {14} {15} {16}]] 
[[{11} {12} {13} {14}] [{21} {22} {23} {24}] [{31} {32} {33} {34}] [{41} {42} {43} {44}]]