給出下面的示例數據,如何獲取time
的每分鐘只有一行?Mysql Group by time by mutilple condition
然後我需要做這樣的條件:
SELECT IF (`Flag` IS NOT NULL,
[fetch flag row],
[otherwise fetch one row from that minute]);
的樣本數據
ID Rate Flag time
1 68.65 null 2012-04-18 10.00.01
2 68.63 null 2012-04-18 10.00.11
3 68.68 null 2012-04-18 10.00.21
4 68.70 null 2012-04-18 10.00.31
5 68.71 null 2012-04-18 10.00.41
6 68.60 null 2012-04-18 10.00.51
7 68.64 null 2012-04-18 10.01.01
8 68.75 null 2012-04-18 10.01.11
9 68.72 1 2012-04-18 10.01.21
10 68.63 null 2012-04-18 10.01.31
11 68.62 null 2012-04-18 10.01.41
12 68.60 null 2012-04-18 10.01.51
Expected Output
1 68.65 null 2012-04-18 10.00.01
9 68.72 1 2012-04-18 10.01.21
這是我到目前爲止有:
SELECT FLAG as signal, DATE_FORMAT(TIME, '%Y-%m-%d %H:%i') as time, RATE as rate
FROM RATES WHERE (FLAG!='' || (DATE_FORMAT(TIME, '%s')>50))
GROUP BY time
ORDER BY time DESC,FLAG DESC;
謝謝您幫幫我。
尼基爾
SELECT FLAG作爲信號,DATE_FORMAT(TIME, '%Y-%間 - %d%H:%I')隨着時間,速率速率FROM價格WHERE(FLAG !=''||(DATE_FORMAT(TIME,'%s')> 50))GROUP BY time ORDER BY time DESC,FLAG DESC – user1340004 2012-04-18 00:00:13