搜索對象和.push到新位置

Question

我試圖將句子從一個地方推到另一個地方。

這一切都取決於找到哪些關鍵字。如果一個句子有兩個關鍵字，那麼它會被推送到第一個關鍵字。

• 貓 - 推貓在他們所有的句子keywordsFound.cats
• 狗 - 推動與狗在他們所有的句子keywordsFound.dogs
• hamst - 全押句子倉鼠他們keywordsFound.hamsters

var data = "I have an oriental cat. I have both a dog and a cat. I always takes care of my American shorthair cat. I have a Birman cat. My parents bought me two Golden Retriever dogs. My dog is a German Shepherd. I always wanted a hamster. I don't have a pet." 
 

 
var userInput = { 
 
    all: [ 
 
    "I have an oriental cat.", 
 
    "I have both a dog and a cat.", //Should only push the first one - dog 
 
    "I always take care of my American shorthair cat.", 
 
    "I have a Birman cat.", 
 
    "My parents bought me two Golden Retriever dogs.", 
 
    "My dog is a German Shepherd.", 
 
    "I always wanted a hamster.", 
 
    "I don't have a pet." 
 
    ], 
 
    keywordsFound: { 
 
    cats: [/*Push all sentences with cat here*/], 
 
    dogs: [/*Push all sentences with dog here*/], 
 
    hamsters: [/*Push all sentences with hamster here*/] 
 
    }, 
 
    noKeywordsFound: [], 
 
} 
 

 
function search(term) { 
 
    if (userInput.all.indexOf(term) !== -1) { 
 
    if (term == 'cat') { 
 
    } 
 
    if (term == 'dog') { 
 
    } 
 
    if (term == 'hamster') { 
 
    } 
 

 
    } 
 
    else { 
 
    //Push to noKeywordsFound as an array 
 
    } 
 
} 
 

 
//Which ever comes first gets pushed 
 
search('cat') 
 
search('dog') //Contains 
 
search('hamster') //Contains

Answer 1

好了，你是使用indexOf在正確的軌道上，但您使用的是它在錯誤的地點（userInput.all.indexOf(term)）:)

所以，你應該在search()功能做的是：

1）遍歷userInput.all的每個元素 - 您可以執行常規for循環或使用Array.prototype.reduce()獲取所有匹配的句子。

2）現在每個元素的循環使用indexOf內部，以便查看它是否包含搜索詞

3）插入所需的集合中，如果長期被發現

所以我會稍微改變你的代碼像這樣的：

var userInput = { 
 
    all: [ 
 
    "I have an oriental cat.", 
 
    "I have both a dog and a cat.", //Should only push the first one - dog 
 
    "I always take care of my American shorthair cat.", 
 
    "I have a Birman cat.", 
 
    "My parents bought me two Golden Retriever dogs.", 
 
    "My dog is a German Shepherd.", 
 
    "I always wanted a hamster.", 
 
    "I don't have a pet." 
 
    ], 
 
    keywordsFound: { 
 
    cats: [], 
 
    dogs: [], 
 
    hamsters: [] 
 
    }, 
 
    noKeywordsFound: [], 
 
} 
 

 
function search(term) { 
 
    
 
    // Here you can do a basic for loop, but I'm using reduce function 
 
    var foundItems = null; 
 
    foundItems = userInput.all.reduce(function(found, current){ 
 
    if(~current.indexOf(term)){ 
 
     found.push(current); 
 
    } 
 
    return found; 
 
    }, []); 
 
    
 
    switch(term){ 
 
    case 'cat':{ 
 
     userInput.keywordsFound.cats = foundItems; 
 
    }break; 
 
    
 
    case 'dog':{ 
 
     userInput.keywordsFound.dogs = foundItems; 
 
    }break; 
 
    
 
    case 'hamster':{ 
 
     userInput.keywordsFound.hamsters = foundItems; 
 
    }break; 
 
    } 
 

 
} 
 

 
search('cat'); 
 
console.log('sentence with cats') 
 
console.log(userInput.keywordsFound.cats); 
 
search('dog'); 
 
console.log('sentence with dogs') 
 
console.log(userInput.keywordsFound.dogs); 
 
search('hamster'); 
 
console.log('sentence with hamsters') 
 
console.log(userInput.keywordsFound.hamsters);

Answer 2

嘗試使用ES6箭頭函數String.prototype.includes()和陣列函數Array.prototype.forEach()和Array.prototype.find()來確定正確的key變量推送：userInput.keywordsFound[key].push(str)。

代碼：

const userInput = { 
 
    all: ["I have an oriental cat.", "I have both a dog and a cat.", "I always take care of my American shorthair cat.", "I have a Birman cat.", "My parents bought me two Golden Retriever dogs.", "My dog is a German Shepherd.", "I always wanted a hamster.", "I don't have a pet."], 
 
    keywordsFound: { 
 
     cats: [], 
 
     dogs: [], 
 
     hamsters: [] 
 
    }, 
 
    noKeywordsFound: [], 
 
    }, 
 
    search = term => { 
 
    userInput.all.forEach(str => { 
 
     const key = Object.keys(userInput.keywordsFound).find(k => k.includes(term)); 
 
     key && str.includes(term) && userInput.keywordsFound[key].push(str); 
 
    }); 
 
    }; 
 

 
//Which ever comes first gets pushed 
 
search('cat'); 
 
search('dog'); //Contains dog 
 
search('hams'); //Contains hamst 
 

 
console.log(userInput.keywordsFound);