2012-03-01 65 views
0

我寫了一個方法,填充由m×n矩陣表示的位圖。我想要做的是將初始像素推入堆棧,然後在一個while循環中從堆棧中彈出一個元素,對它進行着色,並在與初始像素的初始顏色顏色相同的情況下推送相鄰像素。棧不斷彈出相同的元素

public void fill(int x, int y, char c) { 
    char tempColor = this.bitmap[y - 1][x - 1]; 
    Point currentPoint; 

    Stack<Point> fillStack = new Stack<Point>(); 

    fillStack.push(new Point(x, y)); 

    do { 
     currentPoint = fillStack.pop(); 
//  System.out.println(currentPoint.x + " " + currentPoint.y); 
//  System.out.println("Current state of the stack:"); 
//  for (Point p: fillStack) 
//   System.out.println(p.x + " " + p.y); 
     this.bitmap[currentPoint.y - 1][currentPoint.x - 1] = c; 
     if (currentPoint.y - 1 > 0 && this.bitmap[currentPoint.y - 2][currentPoint.x - 1] == tempColor) { 
      fillStack.push(new Point(x, y - 1)); 
//   System.out.println("Pushing " + currentPoint.x + " " + (currentPoint.y - 1)); 
     } 
     if (currentPoint.y - 1 < n - 1 && this.bitmap[currentPoint.y][currentPoint.x - 1] == tempColor) { 
      fillStack.push(new Point(x, y + 1)); 
//   System.out.println("Pushing " + currentPoint.x + " " + (currentPoint.y + 1)); 
     } 
     if (currentPoint.x - 1 > 0 && this.bitmap[currentPoint.y - 1][currentPoint.x - 2] == tempColor) { 
      fillStack.push(new Point(x - 1, y)); 
//   System.out.println("Pushing " + (currentPoint.x - 1) + " " + currentPoint.y); 
     } 
     if (currentPoint.x - 1 < m - 1 && this.bitmap[currentPoint.y - 1][currentPoint.x] == tempColor) { 
      fillStack.push(new Point(x + 1, y));  
//   System.out.println("Pushing " + (currentPoint.x + 1) + " " + currentPoint.y); 
      } 
     } while (!fillStack.isEmpty()); 
    } 
} 

但它不起作用,因爲我似乎無法找到。輸出(調試線未註釋)如下:

 
3 3 
Current state of the stack: 
Pushing 3 2 
Pushing 3 4 
Pushing 4 3 
4 3 
Current state of the stack: 
3 2 
3 4 
Pushing 4 2 
Pushing 4 4 
Pushing 5 3 
4 3 
Current state of the stack: 
3 2 
3 4 
3 2 
3 4 
Pushing 4 2 
Pushing 4 4 
Pushing 5 3 
4 3 
Current state of the stack: 
3 2 
3 4 
3 2 
3 4 
3 2 
3 4 
Pushing 4 2 
Pushing 4 4 
Pushing 5 3 
4 3 
Current state of the stack: 
3 2 
3 4 
3 2 
3 4 
3 2 
3 4 
3 2 
3 4 
Pushing 4 2 
Pushing 4 4 
Pushing 5 3 
4 3 
Current state of the stack: 
3 2 
3 4 
3 2 
3 4 
3 2 
3 4 
3 2 
3 4 
3 2 
3 4 
Pushing 4 2 
Pushing 4 4 
Pushing 5 3 
4 3 
Current state of the stack: 
3 2 
3 4 
3 2 
3 4 
3 2 
3 4 
3 2 
3 4 
3 2 
3 4 
3 2 
3 4 
Pushing 4 2 
Pushing 4 4 
Pushing 5 3 
4 3 
Current state of the stack: 
3 2 
3 4 
3 2 
3 4 
3 2 
3 4 
3 2 
3 4 
3 2 
3 4 
3 2 
3 4 
3 2 
3 4 
Pushing 4 2 
Pushing 4 4 
Pushing 5 3 
4 3 
Current state of the stack: 
3 2 
3 4 
3 2 
3 4 
3 2 
3 4 
3 2 
3 4 
3 2 
3 4 
3 2 
3 4 
3 2 
3 4 
3 2 
3 4 
Pushing 4 2 
Pushing 4 4 
Pushing 5 3 
4 3 
Current state of the stack: 
3 2 
3 4 
3 2 
3 4 
3 2 
3 4 
3 2 
3 4 
3 2 
3 4 
3 2 
3 4 
3 2 
3 4 
3 2 
3 4 
3 2 
3 4 

...並且它在這樣一個無限循環中繼續。可能是什麼問題?

回答

3

您的打印語句說一件事,您的代碼做了另一件事! ;)

例如:

fillStack.push(new Point(x, y - 1)); 
System.out.println("Pushing " + currentPoint.x + " " + (currentPoint.y - 1)); 

看看你是否能看出其中的區別...

+0

哦,我,我不敢相信,我一直在尋找這個東西了一個小時,couldn看不到這個。謝謝:D – hattenn 2012-03-01 11:23:42

+2

@hatten - 哈哈,有時你需要的是另一雙眼睛...... – Nim 2012-03-01 11:24:38