我在這個程序的最後部分有問題。我如何顯示已彈出的元素?在C++中顯示彈出的元素?
我試圖改變循環,但不能..
#include<iostream.h>
typedef struct TINDANAN
{
int atas;
char senarai[4];
} tindanan;
void cipta(tindanan *t);
void push(tindanan *t);
void pop(tindanan *t);
int penuh(tindanan *t);
int kosong(tindanan *t);
void main()
{
int pilihan,jawapan,i;
tindanan t;
cipta(&t);
cout<<"\n1->Push\t\n 2->Pop \t\n 3-> Keluar \n pilihan =";
cin>>pilihan;
while(pilihan !=3)
{
switch (pilihan)
{
case 1: push(&t);
break;
case 2: pop(&t);
break;
default : cout<<"\nTidak Sah";
}
cout<<"\n1->Push\t\n 2->Pop \t\n 3-> Keluar \n pilihan =";
cin>>pilihan;
}
}
void cipta (tindanan *t)
{
t->atas =-1;
}
int penuh (tindanan *t)
{
if (t->atas ==3)
return (1);
else
return (0);
}
void push (tindanan *t)
{
int i;
char data;
if (penuh(t) ==1)
cout<<"\nTindanan Penuh\n";
else
{
cout<<"\nHuruf Character: ";
cin>>data;
t->atas++;
t->senarai[t->atas]=data;
cout<<"\nKandungan Timbunan :\nIndex | Data\n";
for(i=t->atas;i>-1;i--)
cout<<"| "<<i<< " | "<< t->senarai[i];
}
cout<<"\n";
}
int kosong (tindanan *t)
{
if (t->atas ==-1)
return (1);
else
return (0);
}
void pop (tindanan *t)
{
int i;
if(kosong(t) == 1)
cout<<"\nTindanan Kosong\n";
else
{
t->atas--;
cout<<"\nkandungan Timbunan :\nIndex | data\n";
for(i=t->atas;i>-1;i--)
cout<<" | "<<i<< " | "<<(t->senarai[i]);
cout<<"\nPop Item";
for(i=3;i>t->atas;i--)
cout<<"| "<<i<< " | "<< t->senarai[i];
}
}
對不起,我只是學習C今年++。
將其翻譯成英文將是一個不錯的第一步。 – 2013-03-04 16:44:25
如果您修復代碼格式,您可能會得到更多答案。添加標籤等。還沒有見過''在一段時間內用過! –
2013-03-04 16:45:05
你想展示每個itme都會彈出嗎? – lokoko 2013-03-04 16:45:27