這個C++代碼彩票猜謎遊戲有什麼問題？

我正在製作一個簡單的彩票遊戲應用程序，其中生成0到10之間的三個隨機數字，如果用戶以正確的順序獲得全部三個，他們將得到100萬。如果他們得到一個權利，那麼他們贏得10美元，如果他們得到全部三個，但不是爲了他們贏得一千，如果兩個匹配，然後他們得到1000美元。如果他們沒有得到任何權利，那麼他們什麼也得不到這個C++代碼彩票猜謎遊戲有什麼問題？

這裏是我的代碼在這裏。

INT主要（）{

cout << "Hello, this is the lottery! Three random numbers between 0 and 10 will be generated. Guess what they are and the order!" << endl; 
char answer; 
cout << "Do you want to play? (y or n): " << endl; 
cin >> answer; 
while (answer == 'y' || 'Y') 

{ 
    srand((unsigned)time(NULL)); 
    int ran1 = rand() % 10; 
    int ran2 = rand() % 10; 
    int ran3 = rand() % 10; 
    int guess1, guess2, guess3; 
    cout << "Enter your first number guess: " << endl; 
    cin >> guess1; 
    cout << "Enter your second number guess: " << endl; 
    cin >> guess2; 
    cout << "Enter your third number guess: " << endl; 
    cin >> guess3; 
    if ((guess1 != ran1 || ran2 || ran3) && (guess2 != ran1 || ran2 || ran3) && (guess3 != ran1 || ran2 || ran3)) 
     cout << "You won no money. Sucks for you." << endl; 
    else 
     if ((guess1 == ran1 || ran2 || ran3) || (guess2 == ran1 || ran2 || ran3) || (guess3 == ran1 || ran2) || ran3) 
      cout << "You won 10 dollars!" << endl; 
     else 
      if ((guess1 && guess2 == ran1 && ran2) || (guess1 && guess3 == ran1 && ran3) || (guess2 && guess3 == ran2 && ran3)) 
       cout << "You won 100 dollars!" << endl; 
      else 
       if ((guess1 == ran1 || ran2 || ran3) && (guess2 == ran1 || ran2 || ran3) && (guess3 == ran1 || ran2 || ran3)) 
        cout << "You won 1 thousand dollars! good job!" << endl; 
       else 
        if ((guess1 == ran1) && (guess2 == ran2) && (guess3 == ran3)) 
         cout << "You won 1 million dollars! jackpot!" << endl; 

    cout << "The numbers were " << ran1 << "," << ran2 << "," << ran3 << endl; 
    cout << "Play again?(y or n): " << endl; 
    cin >> answer; 
    if (answer == 'y') 
     continue; 
    else 
     break; 

} 



cout << "Game Over" << endl; 
system("pause"); 
return 0;

}

當我運行這段代碼，事情不正確就決定去了。它所說的是「你沒有贏錢，爲你吸引」。 Idk有什麼不對，也許它有些簡單，但有人可以幫忙嗎？謝謝。

來源

2017-09-25 Live Strong

'guess1！= ran1 || ran2 || ran3'不會做你認爲的事 – vu1p3n0x

它有什麼問題？ –

看到Sadovsky的答案在下面，你也應該改變你的'if'的順序，即使你猜對了，你也會贏10美元，因爲它滿足條件（和之前的條件） – vu1p3n0x

if ((guess1 != ran1 || ran2 || ran3) && (guess2 != ran1 || ran2 || ran3) && (guess3 != ran1 || ran2 || ran3))

應該

if ((guess1 != ran1 || guess1 != ran2 || guess1 != ran3) && (guess2 != ran1 || guess2 != ran2 || guess2 != ran3) && (guess3 != ran1 || guess3 != ran2 || guess3 != ran3))

來源

2017-09-25 23:30:37

這不是條件語句的順序，即使有瑕疵有作爲，但在你所寫的條件語句的方式。

（guess1 == RAN1 || RAN2）比（guess1 == RAN1 || guess1 == RAN2）

這是因爲在C++ 0以外的數的計算結果爲真不同。這就是爲什麼它每次都評估爲真。

例如，假設guess1 = 1，RAN1 = 2，RAN2 = 3，然後

（guess1 == RAN1 || guess1 == RAN2）將評估爲假，但是

（guess1 == ran1 || ran2）將評估爲true。

來源

2017-09-26 00:51:37 JDollars

這個C++代碼彩票猜謎遊戲有什麼問題？

回答

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