用while語句循環，而讀一字符串整數

Question

我需要幫助包住：

if any(c.isdigit() for c in name): 
print("Not a valid name!") 

while語句的內部。這幾乎只是讀取「name」變量的輸入，並查看是否有一個整數。我怎麼能在一個while語句中使用它？我只是希望如果用戶在輸入中輸入了一個變量，它會打印出上面的字符串並循環回去，並再次詢問用戶名稱，直到他們成功輸入一個沒有整數的字符串，然後我想要它打破。任何幫助？

print("Hello there!") 
yn = None 
while yn != "y": 
    print("What is your name?") 
    name = raw_input() 
    if any(c.isdigit() for c in name): 
     print("Not a valid name!") 
    print("Oh, so your name is {0}? Cool!".format(name)) 
    print("Now how old are you?") 
    age = raw_input() 
    print("So your name is {0} and you're {1} years old?".format(name, age)) 
    print("y/n?") 
    yn = raw_input() 
    if yn == "y": 
     break 
    if yn == "n": 
     print("Then here, try again!") 
print("Cool!") 

Answer 1

使用while True和break結束循環時，已經進入了一個有效的名稱：

while True: 
    name = raw_input("What is your name? ") 
    if not any(c.isdigit() for c in name): 
     break 
    print("Not a valid name!") 

這比第一初始化name的東西，是無效的，那麼用在any()表達更容易while測試。

Answer 2

事情是這樣的：

name = input("What is your name? : ") 
while any(c.isdigit() for c in name): 
    print ("{0} is invalid, Try again".format(name)) 
    name = input("What is your name? : ") 

演示：

What is your name? : foo1 
foo1 is invalid, Try again 
What is your name? : 10bar 
10bar is invalid, Try again 
What is your name? : qwerty 

Answer 3

你只是說你想要一個continue後您的print("Not a valid name!")？

print("Hello there!") 
yn = None 
while yn != "y": 
    print("What is your name?") 
    name = raw_input() 
    if any(c.isdigit() for c in name): 
     print("Not a valid name!") 
     continue 
    print("Oh, so your name is {0}? Cool!".format(name)) 
    ... 

continue將回到您的循環的頂部。