4
我試圖用動作來縮放我的Actor。 但它不起作用。我只是希望我的演員在給定的時間內增加/減少它的尺寸。ScaleTo不能在Libgdx工作
演員將等待我給予ScaleTo
的2秒持續時間。它會根據我給出的MoveTo
操作正確移動。
public class SpriteTest extends Actor {
private Sprite sprite;
private TextureAtlas atlas;
Rectangle boundsd = new Rectangle();
public SpriteTest(FirstGame game) {
//super(game);
Gdx.app.log(FirstGame.LOG, "spritetest's costructor");
atlas = new TextureAtlas(Gdx.files.internal("pages-info.atlas"));
sprite = atlas.createSprite("Plus");
}
public void draw(SpriteBatch batch,float parentAlpha) {
batch.draw(sprite, x, y);
}
// We are adding the actor to the stage in another class
public class LevelScreen extends AbstractScreen {
private Jumper2D jumper2d;
SpriteTest obstacled = new SpriteTest(game);
public LevelScreen(FirstGame game) {
super(game);
}
@Override
protected boolean isGameScreen() {
return true;
}
@Override
public void show() {
super.show();
stage.addActor(obstacled);
obstacled.action
(Forever.$
(Sequence.$
(ScaleTo.$(1.4f, 1.4f, 2),(MoveTo.$(100,120, 3f)))
));
jumper2d = Jumper2D.create(getAtlas());
stage.addActor(jumper2d);
stage.draw();
}
public void render() {
Gdx.gl.glClear(GL10.GL_COLOR_BUFFER_BIT);
stage.act(Math.min(Gdx.graphics.getDeltaTime(), 1/30f));
stage.draw();
}
}
任何幫助表示讚賞
得到它 感謝很多:) – Silentasssasssin 2013-02-28 19:03:44
@Silentasssasssin歡迎計算器。如果我的答案回答您的問題,請將其標記爲「已接受」(點擊左側的複選標記)。請參閱常見問題了解更多詳情http://stackoverflow.com/faq#howtoask – 2013-03-01 15:28:13
謝謝,這很明顯,但是當你開始libgdx(就像我)這是一個非常常見的錯誤,可以讓你花幾個小時找到它。 – Don 2014-03-22 16:12:33