在matlab中繪製光分佈曲線的2D和3D c-平面

Question

我想繪製分別描述2D和3D空間中光源的光分佈曲線（LCD）的C-平面。通常，製造商在極座標中提供ldc的詳細信息。一個例子在下面可以看到：

與圖表

一起（紅線固體/虛線表示C面）

上述2D圖中可以繪製仿真軟件相當漂亮，如下圖所示：

現在，如果有可能，我想在matlab中繪製相同的圖/圖。但是，我不知道該怎麼做。對於2D圖，我查看了polarplot()函數，但我不確定我的輸入應該基於我的矩陣。關於3D情節，我完全不知道如何在3D空間中獲得情節。因此，如果有人能夠給我提供一些提示或解決方案，那將非常有幫助。以下是上述矩陣的值，以防有人想要試驗它。

非常感謝提前。

---

更新：

好的策劃可以用下面的代碼可以實現2D極圖：

ldc = [426.0060 426.0060 426.0060 426.0060 426.0060 426.0060 426.0060 
    424.7540 425.0980 425.5810 425.9940 425.6490 425.1670 424.7540 
    421.8600 422.2040 422.7550 423.1690 422.6860 422.2040 421.8600 
    415.5200 416.0020 416.1400 416.8980 416.6910 416.2780 415.7960 
    408.6290 406.9060 407.0440 408.0090 409.0420 407.3890 406.5620 
    394.1580 394.2960 394.5030 395.1920 395.0540 394.5720 394.5720 
    374.5880 375.8290 376.9310 376.6550 374.6570 376.3800 377.4820 
    349.7810 351.3660 352.8130 351.9170 350.7460 352.1930 353.9150 
    317.8070 316.2910 318.2210 316.2910 316.8420 317.1870 319.8750 
    267.2280 269.4330 264.4720 267.9170 267.9170 269.6400 266.1260 
    200.4280 162.1010 174.1260 163.2380 199.5320 163.8650 174.8770 
    111.4940 118.7160 150.0280 118.3780 112.6450 116.1870 151.6540 
    73.5810 78.4390 99.5180 80.3960 75.7450 78.4250 100.4280 
    49.7660 69.2120 54.2240 71.2930 52.1980 71.8860 56.8360 
    35.5290 49.5180 46.4930 48.3810 35.8390 47.2780 48.2220 
    34.3720 37.9410 35.3290 38.5750 33.9930 39.9950 35.4050 
    24.1730 24.9380 28.9690 25.8750 24.7800 24.6350 28.5140 
    14.3050 15.9870 19.6670 16.4830 15.1460 15.9450 19.7770 
    6.0920 6.5390 7.0420 7.2350 6.9940 6.8220 6.6840 
    4.7550 4.9550 5.2780 5.2160 5.2090 5.4780 5.6640 
    3.8590 3.8520 3.8930 3.9000 3.8870 4.3210 4.4380 
    3.1150 3.1420 2.9350 2.8530 3.0870 3.4660 3.5970 
    2.8670 2.6670 2.4740 2.3500 2.5700 2.9290 3.1700 
    2.4120 2.4050 2.3360 2.0330 2.3500 2.6050 2.7840 
    1.6540 1.6670 1.9090 1.8880 1.7300 1.5920 1.6810 
    1.1300 1.1990 1.2680 1.4880 1.2270 1.1580 1.1300 
    1.0470 1.0400 1.0400 1.1440 1.0750 1.0540 1.0470 
    1.1300 1.1640 1.2060 1.1850 1.2130 1.1850 1.1710 
     0   0   0   0   0   0   0 
     0   0   0   0   0   0   0 
     0   0   0   0   0   0   0 
     0   0   0   0   0   0   0 
     0   0   0   0   0   0   0 
     0   0   0   0   0   0   0 
     0   0   0   0   0   0   0 
     0   0   0   0   0   0   0 
     0   0   0   0   0   0   0]; 

color = 'r'; 
line = '-'; 
% plotting only the first and the last C-planes, i.e. 0 and 90 degrees respectively 
for i = 1:6:size(ldc,2) 
    polarplot(degtorad(theta),ldc(:,i), 'Color', color, 'LineStyle', line, 'LineWidth', 1.5) 
    hold on 
    polarplot(-degtorad(theta),ldc(:,i), 'Color' ,color, 'LineStyle', line, 'LineWidth', 1.5) 
    line = ':'; 
end 

ax = gca; 
ax.ThetaZeroLocation = 'bottom'; 
ax.RAxisLocation = 0; 
ax.ThetaTickLabel = {'0'; '30'; '60'; '90'; '120'; '150'; '180'; '150'; '120'; '90'; '60'; '30';}; 

Answer 1

我還沒有試過，但你可以轉換使用pol2cart將極座標轉換爲笛卡爾座標，然後將第三維和使用fill3來渲染曲面。

好吧，我猶豫了，在這裏實現它：

% range of angles 
angles = 0:0.01:(2*pi); 

% light intensity example (insert values from table) 
r = 1 + sin(angles); 

% convert to cartesian coordinates 
[p1, p2] = pol2cart(angles, r); 

% plot on x-axis (x=0) 
X = zeros(size(p1)); 
Y = p1; 
Z = p2; 
C = ones(size(Z)); % color input needed 
fill3(X,Y,Z,C) 
hold on 

% plot on y-axis (y=0) 
X = p1; 
Y = zeros(size(p1)); 
Z = p2; 
C = ones(size(Z))+1; 
fill3(p1,zeros(size(p1)),p2,C) 

xlabel('x') 
ylabel('y') 
zlabel('z') 
grid on 

對於特定的數據集，你可以做以下

% angles around x-axis, need to turn by 90 degree right pol2cart output 
anglesX = (0:5:360)/180*pi+pi/2; 

% angles around z-axis 
anglesZ = 0:15:90; 

% loop over columns 
for i = 1:size(ldc,2) 

    % you need to create a closed contour for fill3 
    ldcJoined = [ldc(:,i);ldc((end-1):-1:1,i)]; 

    % plot for positive and negative angle around z, i as color-index 
    plotPlane(anglesX, ldcJoined, anglesZ(i), i) 
    hold on 
    plotPlane(anglesX, ldcJoined, -anglesZ(i), i) 
end 

xlabel('x') 
ylabel('y') 
zlabel('z') 

function [] = plotPlane(anglesX, r, angleZ, c) 

    % convert to cartesian coordinates 
    [p1, p2] = pol2cart(anglesX, r'); 

    % plot on x-axis (x=0) 
    X = zeros(size(p1)); 
    Y = p1; 
    Z = p2; 
    C = ones(size(Z)) .* c; % color input needed, you could e.g. C=sin(angles); 
    h = fill3(X,Y,Z,C); 
    rotate(h, [0,0,1], angleZ) 

end 

其中給出