應用將跳過打印程序涉及變量的前10個數值的continue語句

Question

我需要應用將跳過打印前10個值的continue語句。

我已經有我的代碼

public class numbers { 

    public static void main(String[] args) { 

     for (int number=1; number <= 99; number++){ 

      if (number % 2 == 0) 
       System.out.print(number + " "); 

         System.out.println(); 
      } 
     } 
    } 

Answer 1

只要有另一個櫃檯

int count = 0; 
    for (int number=1; number <= 50; number++){ 

     if (number % 2 == 0 && count++ >= 10) 
     { 
      System.out.print(number + " "); 
      System.out.println(); 
     } 
    } 

，或者如果你想使用一個繼續

int count = 0; 
    for (int number=1; number <= 50; number++){ 

     if (number % 2 == 0) 
     { 
      if (count++ < 10) 
        continue; 

      System.out.print(number + " "); 
      System.out.println(); 
     } 
    } 

Answer 2

添加計數器：

public static void main(String[] args) { 
    int counter = 0; 
    for (int number = 1; number <= 50; number++) { 
     if (number % 2 == 0) { 
      counter++; 
      if (counter <= 10) { 
       continue; 
      } 
      System.out.println(number + " "); 
     } 
    } 
} 

與Java 8 Stream的IT可以更文筆優美：

IntStream.rangeClosed(1,50).filter(i -> i % 2 == 0).skip(10).forEach(System.out::println);