2016-04-22 85 views
0

如何合併2個(結構相同)的JSON對象(在Google Spreadsheet腳本中)?在GAS中合併2個JSON對象(無jquery)

{"records":[{"id":28100988,"work_text_reviews_count":13,"average_rating":"3.10"},{"id":10280687,"work_text_reviews_count":80,"average_rating":"3.87"}]} 

{"records":[{"id":16135639,"work_text_reviews_count":0,"average_rating":"0.00"},{"id":17978337,"work_text_reviews_count":2414,"average_rating":"3.76"{"id":360721218,"work_text_reviews_count":4924,"average_rating":"3.98"}]} 

合併後的結果應該是:

{"records":[{"id":28100988,"work_text_reviews_count":13,"average_rating":"3.10"},{"id":10280687,"work_text_reviews_count":80,"average_rating":"3.87"},{"id":16135639,"work_text_reviews_count":0,"average_rating":"0.00"},{"id":360721218,"work_text_reviews_count":4924,"average_rating":"3.98"}]} 

由於這在谷歌電子表格,我不能使用JQuery,我已經用了一整天的JavaScript的解決方案,我不能讓工作沒有錯誤。

回答

1

你可以使用concat

var json1 = { 
    "records": [{ 
    "id": 28100988, 
    "work_text_reviews_count": 13, 
    "average_rating": "3.10" 
    }, { 
    "id": 10280687, 
    "work_text_reviews_count": 80, 
    "average_rating": "3.87" 
    }] 
} 

var json2 = { 
    "records": [{ 
    "id": 16135639, 
    "work_text_reviews_count": 0, 
    "average_rating": "0.00" 
    }, { 
    "id": 17978337, 
    "work_text_reviews_count": 2414, 
    "average_rating": "3.76" 
    }, { 
    "id": 360721218, 
    "work_text_reviews_count": 4924, 
    "average_rating": "3.98" 
    }] 
} 


var json3 = json1.records.concat(json2.records);