需要多個JPanel來響應它自己的鼠標點擊事件

Question

我的應用程序有多個JPanel，但我無法弄清楚如何檢測到哪一個被點擊。

在我的MouseListener，我的說法，但ê我的方法是行不通的

早在我的代碼聲明多個JPanels和偵聽器對象。

PuzzleListener plist = new PuzzleListener(); 
JPanel puzzle_board = new JPanel(new GridLayout(4,4,5,5)); 
... 
Square square1 = new Square("1"); 
Square square2 = new Square("2"); 
... 
puzzle_board.add(square1); 
puzzle_board.add(square2); 
... 
square1.addMouseListener(plist); 
square1.addMouseListener(plist);
 

class PuzzleListener implements MouseListener {
 

public void mouseClicked(MouseEvent e) 
{ 
     JPanel pnlClick = (JPanel)(e.getSource()); 
     //System.out.println(pnlClick); 
    //System.out.println(e.getSource()); 
    //System.out.println(e.getComponent().getClass()); 
    //System.out.println(e.getComponent().getClass().getName()); 


      //problem is here 

    if(pnlClick == square1) 
    { 
    System.out.println("Panel 1 has been clicked"); 
    }  
      if(pnlClick == square2) 
    { 
    System.out.println("Panel 2 has been clicked"); 
    }  
} 
public void mouseExited(MouseEvent e) 
{ 
} 
public void mouseEntered(MouseEvent e) 
{ 
    //System.out.println("Panel 1 has been clicked"); 
} 
public void mouseReleased(MouseEvent e) 
{ 
} 
public void mousePressed(MouseEvent e) 
{ 

} 
/* 
public void actionPerformed(ActionEvent e) 
{ 
    JPanel pnlClick = (JPanel)(e.getSource()); 
}*/ 

}//end calcListener 

Answer 1

的問題似乎是，你有一個類變量和局部變量爲每個正方形面板。

Square square1 = new Square("1"); 

應該是：

square1 = new Square("1"); 

現在你只會有一類變量，它的PuzzleListener可以參考一下。

Answer 2

是否需要使用單個MouseListener？您可以創建一個PuzzleListener的新實例並將其添加到每個JPanel。這樣就不會混淆哪個面板上的哪個監聽器被觸發。