MySQL的 - SQL查詢和與過濾

我想告訴我的查詢僅僅只有誰總訂單更大然後200MySQL的 - SQL查詢和與過濾

現在我的查詢是

SELECT 
    ps_orders.id_customer, 
    ps_customer.firstname, 
    ps_customer.lastname, 
    ps_customer.email, 
    ps_orders.total_paid 
FROM 
    ps_orders 
    RIGHT JOIN ps_customer 
     on ps_orders.id_customer = ps_customer.id_customer 
WHERE 
    ps_orders.total_paid > 1 
ORDER BY 
    ps_orders.id_customer;

顯示這樣

id_customer firstname lastname email total_paid 
-------------------------------------------------------- 
55 name8 name10 ***@windowslive.com 88.90 
58 name6 name7 ****@hotmail.com 56.00 
58 name6 name7 ****@hotmail.com 87.90 
58 name6 name7 ****@hotmail.com 79.99 
58 name6 name7 ****@hotmail.com 78.90 
59 name3 name5 ****@hotmail.com 123.83 
60 name name2 ****@hotmail.com 78.90

我想要這樣的演出

id_customer firstname lastname email total_paid 
-------------------------------------------------------- 
58 name6 name7 ****@hotmail.com 302.49

來源

2015-11-03 ZgrKARALAR

'ps_orders.total_paid> 200 '？ –

@Lashane，其僅示出了訂單更大然後200不使總和 – ZgrKARALAR

值得一提的是，用於搜索「RIGHT JOIN」上SO當前返回1530分的結果，與對「LEFT JOIN」的搜索相比較，其目前返回17960結果。 – Strawberry

Group by ps_orders.id_customer having sum(ps_orders.total_paid) > 200

«分組»通過»將您的數據進行分組並得到總數

編輯：«哪裏»不能做聚合函數。

SELECT ps_orders.id_customer, 
ps_customer.firstname, 
ps_customer.lastname, 
ps_customer.email, 
sum(ps_orders.total_paid) as totalOrder

....... 組由ps_orders.id_customer，ps_customer.firstname，ps_customer.lastname，ps_customer.email具有總和（ps_orders.total_paid）> 200

來源

2015-11-03 23:22:00 juankirr

即拍算了筆該組是好的，但我不希望節目是小於200，如果我作出這樣的表現給我id_customer 60總支付78.90。 – ZgrKARALAR

你有沒有把having子句？ – juankirr

我只是嘗試這樣SELECT ps_orders.id_customer， ps_customer.firstname， ps_customer.lastname， ps_customer.email， ps_orders.total_paid FROM ps_orders RIGHT JOIN上ps_orders.id_customer = ps_customer.id_customer 集團ps_customer 通過ps_orders.id_customer 具有總和（ps_orders.total_paid）> 200 – ZgrKARALAR

MySQL的 - SQL查詢和與過濾

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