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例如鑑於這種urlscrapy css選擇器鏈如何表示當前節點?
我想獲得賣家的DIV
使用XPath,首先我用CSS來得到一個特定的賣家行,然後我用「./」來指代當前節點,那麼我可以得到(5) div放在我的目標div(行)之後。 B的
b = response.css('div#olpOfferList div.a-row.a-spacing-mini.olpOffer')[1].xpath('./div')
結果:
<Selector xpath='./div' data=u'<div class="a-column a-span2 olpPriceCol'>
<Selector xpath='./div' data=u'<div class="a-column a-span3 olpConditio'>
<Selector xpath='./div' data=u'<div class="a-column a-span3 olpDelivery'>
<Selector xpath='./div' data=u'<div class="a-column a-span2 olpSellerCo'>
<Selector xpath='./div' data=u'<div class="a-column a-span2 olpBuyColum'>
但隨着CSS,我也不怎麼選擇當前節點的
a = response.css('div#olpOfferList div.a-row.a-spacing-mini.olpOffer')[1].css('div > div')
結果後指當前節點:
<Selector xpath=u'descendant-or-self::div/div' data=u'<div class="a-column a-span2 olpPriceCol'>
<Selector xpath=u'descendant-or-self::div/div' data=u'<div class="a-column a-span3 olpConditio'>
<Selector xpath=u'descendant-or-self::div/div' data=u'<div class="a-section a-spacing-small">\n'>
<Selector xpath=u'descendant-or-self::div/div' data=u'<div class="a-column a-span3 olpDelivery'>
<Selector xpath=u'descendant-or-self::div/div' data=u'<div class="a-column a-span2 olpSellerCo'>
<Selector xpath=u'descendant-or-self::div/div' data=u'<div class="a-column a-span2 olpBuyColum'>
<Selector xpath=u'descendant-or-self::div/div' data=u'<div class="a-button-stack">\n '>
我試過這個但得到一個錯誤r:
a = response.css('div#olpOfferList div.a-row.a-spacing-mini.olpOffer')[1].css('> div')
如何用css引用當前節點? :D感謝您的幫助!
感謝您澄清我的難題! – Tianqing