結合我有一個數組如下如何數組具有相同索引
[{"2":[2]},{"9":[4,10,11,12,13,14,15,16,17,19,20,21,22,23,24,25,26,27,28,30,32,33,34,36,41]},{"2":[5,6,9]},{"7":[7,8]},{"9":[3]}]
是那裏的值相同的索引合併任何可能的方式?
結合我有一個數組如下如何數組具有相同索引
[{"2":[2]},{"9":[4,10,11,12,13,14,15,16,17,19,20,21,22,23,24,25,26,27,28,30,32,33,34,36,41]},{"2":[5,6,9]},{"7":[7,8]},{"9":[3]}]
是那裏的值相同的索引合併任何可能的方式?
是的,這是可能的解碼JSON字符串並且使用array_reduce:
$arr = json_decode('[{"2":[2]},{"9":[4,10,11,12,13,14,15,16,17,19,20,21,22,23,24,25,26,27,28,30,32,33,34,36,41]},{"2":[5,6,9]},{"7":[7,8]},{"9":[3]}]');
$arr = array_reduce($arr, function ($carry, $item) {
$key = key($item);
if (isset($carry[$key])) {
$carry[$key]->$key = array_merge($carry[$key]->$key, $item->$key);
} else {
$carry[$key] = $item;
}
return $carry;
});
echo json_encode(array_values($arr));
結果是:
[{ 「2」:[2,5,6,9]} ,{ 「9」:[4,10,11,12,13,14,15,16,17,19,20,21,22,23,24,25,26,27,28,30,32,33 ,34,36,41,3]},{ 「7」:[7,8]}]
array_merge():參數#1不是數組,我試過你的解決方案,但我的數組不是字符串..它是一個數組, – CodeGG
@ Matei-Mihai:如果我可以比如說,你甚至可以在第7行執行'sort($ carry [$ key] - > $ key,SORT_NUMERIC);並且按照@ Beshoy-Girgis的方式獲得數組:#^^ – OldPadawan
我自己做錯了,您的解決方案正常工作。感謝matei !! – CodeGG
<?php
$json = '[{"2":[2]},{"9":[4,10,11,12,13,14,15,16,17,19,20,21,22,23,24,25,26,27,28,30,32,33,34,36,41]},{"2":[5,6,9]},{"7":[7,8]},{"9":[3]}]';
$multi_array = json_decode($json, true);
$result = [];
foreach($multi_array as $arr)
{
foreach($arr as $k => $v)
{
$temp = isset($result[$k]) ? $result[$k] : [];
$result[$k] = array_merge($temp, $v);
}
}
print_r($result);
這是另一種選項:
$old = json_decode('[{"2":[2]},{"9":[4,10,11,12,13,14,15,16,17,19,20,21,22,23,24,25,26,27,28,30,32,33,34,36,41]},{"2":[5,6,9]},{"7":[7,8]},{"9":[3]}]', true);
$new = [];
array_map(function ($arr) use (&$new) {
$key = key($arr);
$new[$key] = array_merge(current($arr), !empty($new[$key]) ? $new[$key] : []);
}, $old);
echo json_encode($new);
輸出:
{"2":[5,6,9,2],"9":[3,4,10,11,12,13,14,15,16,17,19,20,21,22,23,24,25,26,27,28,30,32,33,34,36,41],"7":[7,8]}
您的陣列具有相同的密鑰,但差異值,比如說第一物鏡鍵:2 = 2,但後來它的[5,6,9] ,,顯示我們想以什麼格式結尾.. –