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爲什麼以下所有代碼後,我做了po NSKeyedUnarchiver.unarchiveObject(with: (response.request?.httpBody)!)
我得到nil
?響應代碼是400.響應代碼的原因是400,我相信是因爲參數。任何建議爲什麼發生這種情況不良請求狀態代碼400請求後
let urlRequest = NSMutableURLRequest(url: url)
let bodyData = parameters.first!.key + "=" + String(describing: parameters.first!.value)
urlRequest.bind(to: command!)
urlRequest.httpBody = bodyData.data(using: .utf8)
urlRequest.httpMethod = "POST"
urlRequest.allHTTPHeaderFields = NetworkManager.defaultHeaders()
return Alamofire.request(urlRequest.copy() as! URLRequest)
編輯:好了,我更換了一些線條和現在的代碼看起來像這樣和參數不再爲零:
let urlRequest = NSMutableURLRequest(url: url)
let dataParameters: Data = NSKeyedArchiver.archivedData(withRootObject: parameters)
urlRequest.bind(to: command!)
urlRequest.httpBody = dataParameters
urlRequest.httpMethod = HTTPMethod.post.rawValue
urlRequest.allHTTPHeaderFields = NetworkManager.defaultHeaders()
return Alamofire.request(urlRequest.copy() as! URLRequest)
但即使這樣,我收到了400碼。因此,在對郵差進行了一番調查之後,我發現如果我將這樣的主體放在{「xxxxx」:「xxxxxxxxx」}中,它就能正常工作,並且我得到了一個很好的代碼,但是如果我使用了鍵值,那麼它就不會。我如何做這項工作?