我已經查明瞭這段代碼,但無法弄清楚如何解決它。當運行代碼時,爲什麼不提示用戶輸入,而不是Java確定沒有輸入?下面的錯誤跟蹤。爲什麼此代碼獲取Java NoSuchElement異常?
import java.util.*;
public class SortAsInserted {
public static void main(String[] args) {
int array_size = GetArraySize();
//System.out.println(array_size);
String[] myArray = new String[array_size];
for (int i = 0; i < array_size; i++){
String next_string = GetNextString();
System.out.println(next_string);
}
}
//public static String[] SortInsert(String nextString){
//}
public static int GetArraySize(){
Scanner input = new Scanner(System.in);
System.out.print("How many items are you entering?: ");
int items_in_array = input.nextInt();
input.close();
return items_in_array;
}
public static void PrintArray(String[] x) {
for (int i = 0; i < x.length; i++){
System.out.print(x[i]);
}
}
public static String GetNextString(){
Scanner input = new Scanner(System.in);
System.out.println("Enter the next string: ");
String next_string = input.nextLine();
input.close();
return next_string;
}
以下是錯誤 -
How many items are you entering?: 2
Enter the next string:
Exception in thread "main" java.util.NoSuchElementException: No line found
at java.util.Scanner.nextLine(Unknown Source)
at SortAsInserted.GetNextString(SortAsInserted.java:40)
at SortAsInserted.main(SortAsInserted.java:10)
請堅持到Java命名約定,方法應該在'camelCase'中。 –
當您想要繼續從同一個流中讀取時,請勿關閉掃描儀。 – laune
另請參見http://stackoverflow.com/questions/14962082/close-scanner-without-closing-system-in – Bobulous