主義N：M關係未定義指數：joinColumns在BasicEntityPersister.php

Question

我的問題是密切相關的這一個Undefined index: inverseJoinColumns while trying to define ManyToMany relationship between two entities

我試圖找到所有這些都沒有部分書籍。 - > findBy（陣列（ 「部分」=>空）

這是我的實體的配置： EditedBooks

/** 
* @var \Doctrine\Common\Collections\Collection 
* 
* @ORM\ManyToMany(targetEntity="Sections", inversedBy="editedBook") 
* @ORM\JoinTable(name="edited_book_has_section", 
* joinColumns={ 
*  @ORM\JoinColumn(name="edited_book_id", referencedColumnName="id") 
* }, 
* inverseJoinColumns={ 
*  @ORM\JoinColumn(name="section_id", referencedColumnName="id") 
* } 
*) 
*/ 
private $section; 

這是我的實體的配置： 節

/** 
* Bidirectional (INVERSE SIDE) 
* 
* @ORM\ManyToMany(targetEntity="EditedBooks", mappedBy="section") 
*/  
private $editedBook; 

我收到的錯誤

Undefined index: joinColumns in BasicEntityPersister.php

我tryied也只有

/** 
* @var \Doctrine\Common\Collections\Collection 
* 
* @ORM\ManyToMany(targetEntity="Sections", inversedBy="editedBook") 
* @ORM\JoinTable(name="edited_book_has_section") 
*/ 

或切換的定義，但後來我收到此錯誤

You cannot search for the association field '\Entity\EditedBooks#section', because it is the inverse side of an association. Find methods only work on owning side associations. 

解決方法： 今天我試圖解決我的問題，在QueryBuilder的我editedbooksRepository

 $query = $qb->select('books') 
     ->from('Bundle:EditedBooks', 'books') 
     ->leftJoin('books.section', 'sec') 
     ->addSelect('COUNT(sec.id) AS sec_count') 
     ->andWhere('sec_count = 0'); 

但是我receved以下錯誤：

An exception occurred while executing 'SELECT e0_.id AS id0, e0_.doi AS doi1, e0_.isbn_print AS isbn_print2, e0_.isbn_electronic AS isbn_electronic3, e0_.publication_date AS publication_date4, e0_.price_print AS price_print5, e0_.price_electronic AS price_electronic6, e0_.summary AS summary7, e0_.title AS title8, e0_.ongoing AS ongoing9, e0_.pages AS pages10, e0_.illustrations AS illustrations11, e0_.entry_date AS entry_date12, e0_.google_id AS google_id13, e0_.specialIssue_comment AS specialIssue_comment14, e0_.deleted AS deleted15, e0_.specialIssue_id AS specialIssue_id16, COUNT(s1_.id) AS sclr17, e0_.book_series_id AS book_series_id18, e0_.copyright_id AS copyright_id19, e0_.publisher_id AS publisher_id20 FROM edited_books e0_ LEFT JOIN edited_book_has_section e2_ ON e0_.id = e2_.editedbooks_id LEFT JOIN sections s1_ ON s1_.id = e2_.sections_id WHERE sclr17 = 0':

SQLSTATE[42S22]: Column not found: 1054 Unknown column 'sclr17' in 'where clause'

但對我來說好像sclr17存在，我失去的東西嗎？

醜陋的解決方法 我知道這是不應該做的事情，但有時一個人有一個人必須做什麼：

$noSection = new Sections();  
    $noSection->setTitle("Sectionless"); 
    //add all the books 
    $noSection->setEditedBook(new ArrayCollection($books)); 
    //remove the assigned ones 
    foreach($sections as $section){ 
     $sBooks = $section->getEditedBook(); 
     foreach($sBooks as $b){ 
      $noSection->removeEditedBook($b); 
     } 
    } 

隨着髒修復它現在的工作，但我很高興爲任何其他解決方案。

Answer 1

這裏是一個工作示例

class Audio 
    { 
     /** 
     * @ORM\ManyToMany(targetEntity="Acme\MyBundle\Entity\Groupe",inversedBy="audios") 
     */ 
     private $groupes; 

    class Groupe 
    { 

    /** 
    * @ORM\ManyToMany(targetEntity="Acme\MyBundle\Entity\Audio",mappedBy="groupes") 
    */ 
    private $audios; 

通知所述的mappedBy和inversedby，以及在屬性如何具有「S」結尾。 （Groupe => private $ groupe s）。也許它會幫助你

Answer 2

你不能只檢查null？

$query = $qb->select('books') 
    ->from('Bundle:EditedBooks', 'books') 
    ->leftJoin('books.section', 'sec') 
    ->where('sec IS NULL');