如何發佈JSON對象在Android下使用Volly Library下面的Json類型？

Question

這裏是我的代碼：

{ 
    "VisitorDetails":[ 
     { 
      "Name":"Ramesh", 
      "Gender":"Male", 
      "Age":24, 
      "MobileNo":9502230173, 
      "LandLine":"040140088", 
      "EmailId":"rameshkandula24@gmail.com", 
      "CreatedOn":"08-25-2016", 
      "Address":"Hyderabad", 
      "Profession":"Software", 
      "FamilyMembers":5, 
      "HomeTown":"Gannavaram", 
      "MedicalHealing":"Noooooo", 
      "Isinterestedwithcompanies":1, 
      "IsBetterlivingStandards":1, 
      "IsInterestedinConference":1, 
      "VisitorExcites":[1,2,3] 
      "jsonkey" : "rUinterested" 

     } 
    ] 
} 

Answer 1

try { 

    JSONArray arry = new JSONArray(); 

    JSONObject iner = new JSONObject(); 

    iner.put("Name", "nmae"); 

    //all detail to iner 

    arry.put(iner); 

    JSONObject outer = new JSONObject(); 

    outer.put("VisitorDetails", arry); 
} 

catch (Exception e){ 
} 

Answer 2

更新：在您的gradle這個添加此（應用級）

compile 'com.android.volley:volley:1.0.0' 

從邦薩爾 ANS發展。

您的JSON數據

JSONArray arry = new JSONArray(); 
     try { 
      JSONObject jsonobject_one = new JSONObject(); 

      jsonobject_one.put("Name", "Name"); 
// add all details like this 

arry.put(jsonobject_one); 
      JSONObject jsonobject_TWO = new JSONObject(); 
      jsonobject_TWO.put("VisitorDetails", arry); 

     }catch (JSONException e) { 
       e.printStackTrace(); 
     } 

然後你jsonRequest

JsonArrayRequest jsonArryReq = new JsonArrayRequest(
     Request.Method.POST,url, arry, 
     new Response.Listener<JSONArray>() { 
      @Override 
      public void onResponse(JSONArray response) { 
       Log.d(TAG, response.toString()); 


      } 
     }, new Response.ErrorListener() { 

      @Override 
      public void onErrorResponse(VolleyError error) { 
       VolleyLog.d(TAG, "Error: " + error.getMessage()); 

      } 
     }) { 

    /** 
    * Passing some request headers 
    * */ 
    @Override 
      protected Map<String, String> getParams() 
      { 
       Map<String, String> param = new HashMap<String, String>(); 
       if (!GetMethod) { 
        param.put("Content-Type", "application/x-www-form-urlencoded;charset=UTF-8"); 
        return param; 
       } 
       return param; 
      } 

Answer 3

final JSONObject jsonObject=new JSONObject(); 
      try { 
       JSONArray jsonArray=new JSONArray(); 

       JSONObject innerobject=new JSONObject(); 

       innerobject.put("Name",Name); 
       innerobject.put("Address",Country); 

       jsonArray.put(innerobject); 

       jsonObject.put("VisitorDetails",jsonArray); 


      }catch (Exception e){ 
       e.printStackTrace(); 
      } 

      JsonObjectRequest jsonObjectRequest = new JsonObjectRequest(Request.Method.POST, URL,jsonObject, new Response.Listener<JSONObject>() { 
       @Override 
       public void onResponse(JSONObject response) { 
        // do something... 
        Toast.makeText(MainActivity.this, "your data successfully register", Toast.LENGTH_SHORT).show(); 
       } 
      }, new Response.ErrorListener() { 
       @Override 
       public void onErrorResponse(VolleyError error) { 
        // do something... 
        Toast.makeText(MainActivity.this, "your data not register", Toast.LENGTH_SHORT).show(); 
       } 
      }) { 

       /** 
       * Passing some request headers 
       */ 
       @Override 
       protected Map<String, String> getParams() { 
        Map<String, String> param = new HashMap<String, String>(); 

         param.put("Content-Type", "application/x-www-form-urlencoded;charset=UTF-8"); 
         return param; 
       } 
      };