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如何從JSON對象的報價:取下JSON對象報價
使用PHP,我得到的數據按以下格式
[
["Catching the Wind in Rural Malawi § SEEDM...", "3"],
["Engineering § SEEDMAGAZINE.COM...", "2"],
["Technology Review India: Nissan's Lea...", "2"],
["Alternative Fuel Consulting & Technical Tr...", "2"],
["MIT OpenCourseWare | Science, Technology, ...", "2"]
]
(使用的console.log()顯示的數據)如何刪除使用jQuery/JSON的報價,我需要這樣的字符串(約數不包括引號):
[
["Catching the Wind in Rural Malawi § SEEDM...", 3],
["Engineering § SEEDMAGAZINE.COM...", 2],
["Technology Review India: Nissan's Lea...", 2],
["Alternative Fuel Consulting & Technical Tr...", 2],
["MIT OpenCourseWare | Science, Technology, ...", 2]
]
你應該接受你的其他問題的答案。 – Kevin 2010-11-22 07:24:50
[沒有這樣的東西作爲「JSON對象」](http://benalman.com/news/2010/03/theres-no-such-thing-as-a-json/) – 2010-11-22 08:07:06