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當進程2沒有變化時，進程2保持激活狀態。我有一塊電路板來測試我的代碼，當我翻動時鐘（我將時鐘設置爲一個按鈕）時，狀態會改變。在我的代碼中，只有我翻動秦纔會改變狀態。所以它沒有做我希望它做的事情，我花了很多時間去試圖找出造成它的原因，但我做不到。請幫忙。如圖所示，在圖中，PS（present_state）的輸出是正確的，但在板中，它不是正確的輸出。我發現有一件事情非常重要，我嘗試輸出next_state，當我將Qin翻轉爲'1'，狀態顯示爲「001」，然後我將clk翻轉爲'1'，狀態變爲「010 「，這不會發生。我希望這是一個重要的信息。當信號的變化，但每次分配的東西信號，即使它像以前那樣具有相同的價值當靈敏度列表不變時，VHDL進程被激活
library IEEE;
use IEEE.STD_LOGIC_1164.ALL;
-- Uncomment the following library declaration if using
-- arithmetic functions with Signed or Unsigned values
--use IEEE.NUMERIC_STD.ALL;
-- Uncomment the following library declaration if instantiating
-- any Xilinx leaf cells in this code.
--library UNISIM;
--use UNISIM.VComponents.all;
entity VendingMechine is
Port (Clk : in STD_LOGIC;
Reset : in STD_LOGIC;
Cr : in STD_LOGIC;
Qin : in STD_LOGIC;
S : in STD_LOGIC;
CB : in STD_LOGIC;
W : in STD_LOGIC;
CRo : out STD_LOGIC_VECTOR(1 DOWNTO 0);
Qo : out STD_LOGIC;
PS : out STD_LOGIC_VECTOR(2 DOWNTO 0);
Wo : out STD_LOGIC;
CBo : out STD_LOGIC;
So : out STD_LOGIC);
end VendingMechine;
architecture Behavioral of VendingMechine is
TYPE state IS(Idle, S1, S2, S3, Soda, Candy, Water);
Signal Next_State : state;
Signal Present_State : state := Idle;
begin
Process1:Process(clk, reset)
begin
if(reset = '1') THEN
Present_State <= Idle;
elsif rising_edge(clk) THEN Present_State <= Next_State;
end if;
end process;
Process2:Process(Qin, Present_State, Cr, S, w)
begin
Next_State <= Present_State;
CRo <= "00"; Qo <= '0'; PS <= "000"; Wo <= '0'; CBo <= '0'; So <= '0';
CASE Present_State IS
When Idle =>
PS <= "000";
if Qin='1' Then Next_State <= S1;
else Next_State <= Idle;
end if;
When S1 =>
PS <= "001";
if Qin='1' Then Next_State <= S2;
elsif Cr = '1' Then Cro <= "01"; Next_State <= Idle;
else Next_State <= S1;
end if;
When S2 =>
PS <= "010";
if Qin='1' Then Next_State <= S3;
elsif Cr = '1' Then CRo <="10"; Next_State <= Idle;
elsif S = '1' Then Next_State <= Soda;
elsif CB = '1' Then Next_State <= Candy;
else Next_State <= S2;
end if;
When S3 =>
PS <= "011";
if Cr = '1' Then CRo <= "11"; Next_State <= Idle;
elsif S = '1' Then Qo <= '1'; Next_State <= Soda;
elsif CB = '1' Then Qo <= '1'; Next_State <= Candy;
elsif W = '1' Then Next_State <= Water;
elsif Qin = '1' Then Qo <= '1';
else Next_State <= S3;
end if;
When Soda =>
PS <= "100";
So <= '1';
Next_State <= Idle;
When Candy =>
PS <= "101";
CBo <= '1';
Next_State <= Idle;
When Water =>
PS <= "110";
Wo <= '1';
Next_State <= Idle;
END CASE;
end process;
end Behavioral;
我說過，當我翻轉Qin，Cr，S，W時，狀態會改變 –
您可以提供一個測試臺來模擬您的代碼並查看它行爲？ – Roman
我在我的線程中添加testbench圖形，看看你是否願意 –