刪除`D型：object`在大熊貓數據幀打印

Question

這裏是我的代碼：

def boba_recs(lat, lng): 
    f1 = pd.read_csv("./boba_final.csv") 
    user_loc = Point(lng, lat) # converts user lat/long to point object 
    # makes dataframe of distances between each boba place and the user loc 
    f1['Distance'] = [user_loc.distance(Point(xy)) for xy in zip(f1.Longitude, f1.Lat)] 
    # grabs the three smallest distances 
    boba = f1.nsmallest(3, 'Distance').set_index('Name') # sets index to name 
    return(": " + boba['Address']) 

這將返回：

Name 
Coco Bubble Tea   : 129 E 45th St New York, NY 10017 
Gong Cha     : 75 W 38th St, New York, NY 10018 
Smoocha Tea & Juice Bar  : 315 5th Ave New York, NY 10016 
Name: Address, dtype: object 

近乎完美，除了我想擺脫「名稱：地址，dtype：object「行。我已經嘗試了一些東西，它不會消除其他所有格式的混亂。

Answer 1

'Address'是pd.Series和'Name'的名稱索引

嘗試的名字：

s.rename_axis(None).rename(None) 

Coco Bubble Tea   : 129 E 45th St New York, NY 10017 
Gong Cha     : 75 W 38th St, New York, NY 10018 
Smoocha Tea & Juice Bar  : 315 5th Ave New York, NY 10016 
dtype: object 

或者我會重寫你的樂趣ction

def boba_recs(lat, lng): 
    f1 = pd.read_csv("./boba_final.csv") 
    user_loc = Point(lng, lat) # converts user lat/long to point object 
    # makes dataframe of distances between each boba place and the user loc 
    f1['Distance'] = [user_loc.distance(Point(xy)) for xy in zip(f1.Longitude, f1.Lat)] 
    # grabs the three smallest distances 
    boba = f1.nsmallest(3, 'Distance').set_index('Name') # sets index to name 
    return(": " + boba['Address']).rename_axis(None).rename(None) 

如果你想有一個字符串

def boba_recs(lat, lng): 
    f1 = pd.read_csv("./boba_final.csv") 
    user_loc = Point(lng, lat) # converts user lat/long to point object 
    # makes dataframe of distances between each boba place and the user loc 
    f1['Distance'] = [user_loc.distance(Point(xy)) for xy in zip(f1.Longitude, f1.Lat)] 
    # grabs the three smallest distances 
    boba = f1.nsmallest(3, 'Distance').set_index('Name') # sets index to name 
    temp = (": " + boba['Address']).rename_axis(None).__repr__() 
    return temp.rsplit('\n', 1)[0] 

Answer 2

這不是一排。這是對您正在打印的數據的描述。嘗試只打印.values，你會看到。

[Coco Bubble Tea   : 129 E 45th St New York, NY 10017 
Gong Cha     : 75 W 38th St, New York, NY 10018 
Smoocha Tea & Juice Bar  : 315 5th Ave New York, NY 10016] 

更新基於您的評論：

print(pd.DataFrame(your_series)) 
Name 
Coco Bubble Tea   : 129 E 45th St New York, NY 10017 
Gong Cha     : 75 W 38th St, New York, NY 10018 
Smoocha Tea & Juice Bar  : 315 5th Ave New York, NY 10016