2013-03-11 49 views
0

我想用backbone.js和mustache來使用Django和tastypie。我已經建立了一個例子來研究這些。如果使用下面的代碼,我得到用戶的結果加倍:Backbone.js提取倍增的結果

  • -Id用戶名
  • -1 YOL
  • -2達達
  • -1 YOL
  • -2達達

---我的代碼---

// I think this tastypie adjustment is not related with the problem but i want you to see the //whole code 

window.TastypieModel = Backbone.Model.extend({ 
     base_url: function() { 
      var temp_url = Backbone.Model.prototype.url.call(this); 
      return (temp_url.charAt(temp_url.length - 1) == '/' ? temp_url : temp_url+'/'); 
     }, 

     url: function() { 
      return this.base_url(); 
     } 
    }); 

    window.TastypieCollection = Backbone.Collection.extend({ 
     parse: function(response) { 
      this.recent_meta = response.meta || {}; 
      return response.objects || response; 
     } 
}); 


(function($){ 



// MODELS-COLLECTIOS 
    //USERS 
    var User = TastypieModel.extend({ 
     url: USERS_API 
    }); 

    var Users = TastypieCollection.extend({ 
     model: User, 
     url:USERS_API 
    }); 



//VIEWS 
    var UsersView = Backbone.View.extend({ 
    render: function(){ 
     // template with ICanHaz.js (ich) 
     this.el = ich.userRowTpl(this.model.toJSON()); 
     return this; 
     } 
    }); 





//main app 
    var AppView = Backbone.View.extend({ 
     tagName: 'tbody', 
     initialize: function() { 
      this.users = new Users(); 
      this.users.bind('all', this.render, this); 
      this.users.fetch(); 
     }, 

     render: function() { 

      // template with ICanHaz.js (ich) 
      this.users.each(function (user) { 
      $(this.el).append(new UsersView({model: user}).render().el); 
      }, this); 



      return this; 
     } 
    }); 

    var app = new AppView(); 
    $('#app').append(app.render().el); 






})(jQuery); 

回答

2

我會說你是射擊兩次渲染,因爲你的觀點是聽所有的事件,而不是嘗試綁定它只是重置,看看它是如何去:

initialize: function() { 
    this.users = new Users(); 
    this.users.bind('reset', this.render, this); 
    this.users.fetch(); 
}, 
+0

謝謝。它解決了雙倍的問題。但是我在** AppView的render **函數中做了一個小測試,並寫了一個'alert('test')'函數。它會調用alert兩次,這意味着它會渲染兩次,這是預期的行爲嗎? – ratata 2013-03-11 14:51:39

+1

是的,因爲你還在調用渲染兩次,第一個'$('#app')。append(app.render()。el);'第二個'this.users.bind('reset',this .render,this);'這是預期的方式,因爲在第一次調用中,集合尚未被提取,因此它正在渲染集合模型的集合是綁定到重置事件的集合,在集合之後觸發它被提取。 – Puigcerber 2013-03-11 15:01:34