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我有一個簡單的模擬D3看起來像這樣的如何刪除D3強制佈局中的節點?
當我點擊「刪除1和4」按鈕,我想從模擬刪除節點1和4。的結果,然而,如下:
目視它似乎已除去3和4(未1和4)。
我的代碼如下。任何想法,我需要做的,以使其正確工作?
我假設我從根本上誤解了更新節點在d3中的工作原理。任何幫助讚賞。 nodeElement = nodeElement.data(nodesData, function(d){ return d.name });
:
<script src="https://cdnjs.cloudflare.com/ajax/libs/d3/3.4.11/d3.min.js"></script>
<!DOCTYPE html>
<meta charset="utf-8">
<script type="text/javascript" src="http://d3js.org/d3.v3.js"></script>
<body>
<button>remove 1 and 4</button>
<script>
var width = 400,
height = 400;
var nodes = [1, 2, 3, 4].map(function(x) { return { name: x}});
var force = d3.layout.force()
.size([width, height])
.nodes(nodes)
.linkDistance(30)
.charge(-500)
.on("tick", tick);
var svg = d3.select("body").append("svg")
.attr("width", width)
.attr("height", height);
var content = svg.append("g");
var nodesData = force.nodes(),
nodeElement = content.selectAll(".node");
function tick() {
nodeElement.attr("transform", function(d) { return "translate(" + d.x + "," + d.y + ")"; });
}
d3.selectAll('button').on('click', function() {
//remove 1 and 4
nodesData = [
nodesData[1],
nodesData[2]
]
refresh();
});
var WIDTH = 100;
//
// this logic is slightly modified from http://bl.ocks.org/tgk/6068367
//
function refresh() {
force.nodes(nodesData)
nodeElement = nodeElement.data(nodesData);
var nodeGroup = nodeElement.enter()
.append('g')
.attr("class", "node");
// node text
nodeGroup.append("text")
.attr("class", "nodetext")
.attr("dx", WIDTH/2)
.attr("dy", "14px")
.text(function(n) { return 'node '+n.name })
nodeElement.exit().remove();
force.start();
}
refresh();
</script>