如何使用另一個鍵的值（整數）拆分字典值

Question

我做了字典。喜歡這個;

output = {} 
output['epoch time'] = obstimes 
output['Number of satellites'] = numsat 
output['OK flag'] = ok_flag 
output['PRN'] = sats 
output['Observation'] = result 
output['Number of each data'] = a 

我必須使用另一個鍵的值來分割字典值。 我展示了這個例子。

{...], 
'Observation': ['22527689.086 7', None, '-578290.975 7', '-410051.96348', '22527682.94948', 
       '20593906.672 7', None, '-142315.266 7', '-103992.19948', '20593902.01648', 
       '22312367.273 6', '22312363.496 9', '-573672.801 6', '-426591.952 9', '22312363.52047', 
       '24649943.453 3', None, '-696710.409 3', '-499047.10745', '24649943.55545', 
       '21574180.359 7', None, '-440212.809 7', '-323130.81248', '21574175.09448', 
       '20159532.789 7', None, '35621.205 7', '26243.45049', '20159527.23449', 
       '24435415.719 6', '24435413.602 9', '417737.346 6', '319304.620 9', '24435413.80147', 
       '23108319.461 5', None, '344109.572 5', '249072.03046', '23108315.90646', 
       '21789481.414 7', None, '326180.505 7', '238895.05548', '21789474.12548', 
       '21975436.727 7', None, '277875.380 7', '205734.181 8', '21975443.121 8', 
       '19981973.117 9', None, '-127270.254 9', '-94211.274 9', '19981980.414 9', 
       '21682862.406 6', None, '242033.680 6', '179454.101 8', '21682869.020 8', 
       '20647552.734 7', None, '-446216.926 7', '-329944.882 9', '20647562.945 9', 
       '23174371.141 6', None, '-645644.090 6', '-481288.202 8', '23174379.656 8', 
       '21946454.047 6', None, '420271.088 6', '311362.996 8', '21946462.590 8', 
       '21922170.063 8', None, '-124733.763 8', '-92183.249 9', '21922177.883 9' 
...],...} 

我想使用另一個值列表來拆分這個'Observation'值。

值的另一個列表是這樣的;

'Number of each data' = [[80, 80, 80, 80, 80, 80, 80, 80, 80, 
80, 80, 80, 80, 80, 80, 80, 80, 75, 80, 80, 80, 65, 75, 75, 75, 
70, 60, 50, 55, 55, 70, 65, 75, 75, 70, 65, 75, 75, 75, 65, 70, 
70, 75, 75.....]] 

我想分割使用每個'每個數據的數量'值的觀測值。

我希望這樣的輸出;

...], 'Observation' : [80 values][80 values][80 values]...} 

請幫忙或給我建議。

Answer 1

你應該遍歷列表「每一個數據的數量」：

output['ObservationMatrix'] = [] 
counter = 0 
for value in output['Number of each data']: 
    output['ObservationMatrix'].append(output['Observation][counter:counter + value]) 
    counter += value 

而在最後，從你的字典