PYTHON：屬性值對拆分列表分爲多鍵字典

Question

我試圖轉換

l = ['attr0=val1, val2', 'attr1=val3,val4'] 

到

d = {attr0: [val1, val2]; attr1: [val3, val4]} 

有效/ pythonically。任何人都知道一個簡潔的方式來做到這一點？

我想是這樣的：

d = {} 
for str in l: 
    k = str.split('=')[0] 
    v = str.split('=')[1] 
    d[k] = [] 
    for item in v.split(','): 
     d[k].append(item) 

Answer 1

In[9]: test = ['attr0=val1, val2', 'attr1=val3,val4'] 
In[10]: result = {} 
    ...: for attribute in test: 
    ...:  key, value = attribute.split('=') 
    ...:  result[key] = [a.strip() for a in value.split(',')] 
    ...: 
In[11]: result 
Out[11]: {'attr0': ['val1', 'val2'], 'attr1': ['val3', 'val4']}