Flex設置stage.mouseChildren爲false可防止使用忙光標

Question

我試圖禁用鼠標單擊並從UIComponent外部顯示忙光標。即時做到這一點：

protected function setBusyCursor() : void { 

     const stage:Stage = mx.core.FlexGlobals.topLevelApplication.stage; 
     if (stage){ 
      stage.mouseChildren = false; 
     } 
     CursorManager.setBusyCursor(); 
    } 

這確實禁用鼠標單擊，但光標出現是正常指針（不忙）。任何想法，我做錯了什麼？

Answer 1

最後我管理這個做到這一點：

protected function setBusyCursor() : void 
    { 
     var i : int = 0; 
     var uiComponent : UIComponent = FlexGlobals.topLevelApplication.parent.getChildAt(i); 
     while (uiComponent != null){ 
      uiComponent.mouseChildren = false; 
      uiComponent.cursorManager.setBusyCursor(); 
      i+=1; 
      if (FlexGlobals.topLevelApplication.parent.getChildAt(i) is UIComponent) { 
       uiComponent = FlexGlobals.topLevelApplication.parent.getChildAt(i); 
      } 
      else { 
       uiComponent = null; 
      } 
     } 
    } 

    protected function removeBusyCursor() : void { 
     var i : int = 0; 
     var uiComponent : UIComponent = FlexGlobals.topLevelApplication.parent.getChildAt(i);   
     while (uiComponent != null){ 
      uiComponent.cursorManager.removeBusyCursor(); 
      uiComponent.mouseChildren = true; 
      i+=1; 
      if (FlexGlobals.topLevelApplication.parent.getChildAt(i) is UIComponent) { 
       uiComponent = FlexGlobals.topLevelApplication.parent.getChildAt(i); 
      } 
      else { 
       uiComponent = null; 
      } 
     } 

    } 

禁用它在屏幕上的所有鼠標點擊，並把繁忙的光標。

Answer 2

所有代碼需要，我測試了4.5.1 flex框架，工作完美。用途：

protected function setBusyCursor() : void 
{  
    FlexGlobals.topLevelApplication.mouseChildren = false; 
    CursorManager.removeAllCursors(); 
    CursorManager.setBusyCursor(); 
}