由於您只有原始的mu律法數據,因此您無法在其上使用WaveFileReader。相反,創建一個從WaveStream繼承的新類。
在其Read
方法中,從tmpMemStream返回數據。作爲WaveFormat
返回mu-law WaveFormat。
這裏,你可以使用一個通用的輔助類:
public class RawSourceWaveStream : WaveStream
{
private Stream sourceStream;
private WaveFormat waveFormat;
public RawSourceWaveStream(Stream sourceStream, WaveFormat waveFormat)
{
this.sourceStream = sourceStream;
this.waveFormat = waveFormat;
}
public override WaveFormat WaveFormat
{
get { return this.waveFormat; }
}
public override long Length
{
get { return this.sourceStream.Length; }
}
public override long Position
{
get
{
return this.sourceStream.Position;
}
set
{
this.sourceStream.Position = value;
}
}
public override int Read(byte[] buffer, int offset, int count)
{
return sourceStream.Read(buffer, offset, count);
}
}
現在,您可以繼續創建你之前做了轉換後的文件,在RawSourceWaveStream傳遞作爲輸入:
var waveFormat = WaveFormat.CreateMuLawFormat(8000, 1);
var reader = new RawSourceWaveStream(tmpMemStream, waveFormat);
using (WaveStream convertedStream = WaveFormatConversionStream.CreatePcmStream(reader))
{
WaveFileWriter.CreateWaveFile(recordingsPath + "/" + outputFileName, convertedStream);
}
謝謝你馬克!這工作完美。 – Sean 2010-11-21 13:03:35
如果我的tmpMemStream是一個文件呢? – Har 2012-06-27 15:22:45