2016-09-26 113 views
0

我有2個表,我使用連接從這兩個表中獲取通用記錄。SQL查詢記錄加倍左加入

我已經使用了下面的查詢,但我的問題是我得到的記錄加倍。

查詢如下,你能幫我嗎?

查詢#1:(正確的輸出)

mysql> SELECT DISTINCT 
    xId1 AS xId1, 
    xArea AS xArea, 
    YEAR (
     STR_TO_DATE(
      `xDate`, 
      '%d/%m/%Y' 
     ) 
    ) AS xYear 
FROM 
    doTable1 AA 
LEFT JOIN doTable2 BB ON AA.xId1 = BB.xId2 
WHERE 
    xArea IN ('XX1A') 
AND YEAR (
    STR_TO_DATE(
     `xDate`, 
     '%d/%m/%Y' 
    ) 
) = 2016; 

+-----------+-------+-------+ 
| xId  | xArea | xYear | 
+-----------+-------+-------+ 
| 91623545 | XX1A | 2016 | 
| 89748942 | XX1A | 2016 | 
| 115956872 | XX1A | 2016 | 
| 103595808 | XX1A | 2016 | 
| 103623873 | XX1A | 2016 | 
| 103623892 | XX1A | 2016 | 
| 103623872 | XX1A | 2016 | 
| 103623894 | XX1A | 2016 | 
| 112072738 | XX1A | 2016 | 
| 112072751 | XX1A | 2016 | 
| 117818773 | XX1A | 2016 | 
| 117818753 | XX1A | 2016 | 
| 117885105 | XX1A | 2016 | 
| 117960040 | XX1A | 2016 | 
| 117885111 | XX1A | 2016 | 
+-----------+-------+-------+ 

15 rows in set 

查詢#2:(不正確的輸出,因爲2016年我有18個記錄 - 加倍的存在 - 而不是15條作爲查詢#1):

mysql> SELECT 
    DISTINCT COUNT(*) AS xQQQ, 
    xArea AS xArea, 
    YEAR (
     STR_TO_DATE(
      xDate, 
      '%d/%m/%Y' 
     ) 
    ) AS xYear 
FROM 
    doTable1 AA 
LEFT JOIN doTable2 BB ON AA.xId1 = BB.xId2 
WHERE xArea IN ('XX1A') 
GROUP BY 
    xArea, 
    xYear; 
+------+-------+-------+ 
| xQQQ | xArea | xYear | 
+------+-------+-------+ 
| 4 | XX1A | 2014 | 
| 49 | XX1A | 2015 | 
| 18 | XX1A | 2016 | 
+------+-------+-------+ 
3 rows in set 
+0

在這些情況下,我將SELECT替換爲SELECT *,然後運行沒有GROUP BY的查詢,並查看每行。沒有完整的數據庫,幾乎不可能猜出問題所在。 – Linkan

+0

@Linkan謝謝yuo的幫助,但是我發佈了**查詢#1 **,沒有** GROUP BY ** –

+0

那str_to_date位似乎有點多餘 – Strawberry

回答

1

修改了你的SQL。如果你想要不同的計數,必須這樣使用

COUNT(DISTINCT xId1) 

請運行並參閱。

SELECT 
     COUNT(DISTINCT xId1) AS xQQQ, 
     xArea AS xArea, 
     YEAR (
      STR_TO_DATE(
       `DATA PUBBLICAZIONE`, 
       '%d/%m/%Y' 
      ) 
     ) AS xYear 
    FROM 
     doTable1 AA 
    LEFT JOIN doTable2 BB ON AA.xId1 = BB.xId2 
    WHERE xArea IN ('XX1A') 
    GROUP BY 
     xArea, 
     xYear; 
+0

非常感謝! –

+0

@AntonioMailtraq總是歡迎。 –