1
我有一個MultiView來添加具有3個視圖的員工。請讓我知道正確的方法。這是我做的不好的代碼，它不工作。每次修改某些內容時都會出現新的錯誤。使用MultiView註冊不起作用
對不起，我這裏無法發示代碼。下面是ASP.NET論壇的帖子
http://forums.asp.net/t/1825476.aspx/1?Registration+using+MultiView+not+working+
namespace EmployeeMultiView.AdminPages
{
public partial class _Default : System.Web.UI.Page
{
protected void Page_Load(object sender, EventArgs e)
{
if (!Page.IsPostBack)
MultiView1.ActiveViewIndex = 0;
}
private void InsertInfo()
{
String KKSTechConnectionString = @"Data Source=USER-PC\SQLEXPRESS;Initial Catalog=KKSTech;Integrated Security=True";
SqlConnection conn = new SqlConnection(KKSTechConnectionString);
//Session["sessFirstName"] = Request["textbox1"];
try
{
conn.Open();
String insertstring = @"Insert INTO Emp
(EmpID,FirstName,LastName,MiddleName,Mob1,Mob2,Phone,Email1,Email2,EmpDesc,Accno,IFSCCode,Branch,ApproxUnitPrice)
values (@EmpID,@FirstName,@LastName,@MiddleName,@Mob1,@Mob2,@Phone,@Email1,@Email2,@EmpDesc,@Accno,@IFSCCode,@Branch,@ApproxUnitPrice)";
if (MultiView1.ActiveViewIndex == 0)
{
SqlCommand cmd = new SqlCommand("insertstring", conn);
cmd.CommandText = insertstring;
cmd.CommandType = CommandType.Text;
cmd.Parameters.AddWithValue("@EmpID", TextBox1.Text);
cmd.Parameters.AddWithValue("@FirstName", TextBox2.Text);
cmd.Parameters.AddWithValue("@LastName", TextBox3.Text);
cmd.Parameters.AddWithValue("@MiddleName", TextBox4.Text);
cmd.Parameters.AddWithValue("@Mob1", TextBox5.Text);
cmd.Parameters.AddWithValue("@Mob2", TextBox6.Text);
cmd.Parameters.AddWithValue("@Phone", TextBox7.Text);
cmd.Parameters.AddWithValue("@Email1", TextBox8.Text);
cmd.Parameters.AddWithValue("@Email2", TextBox9.Text);
cmd.Parameters.AddWithValue("@EmpDesc", TextBox10.Text);
}
else if (MultiView1.ActiveViewIndex == 1)
{
SqlCommand cmd2 = new SqlCommand("insertstring", conn);
cmd2.CommandText = insertstring;
cmd2.CommandType = CommandType.Text;
cmd2.Parameters.AddWithValue("@Accno", TextBox11.Text);
cmd2.Parameters.AddWithValue("@IFSCCode", TextBox12.Text);
cmd2.Parameters.AddWithValue("@Branch", TextBox13.Text);
cmd2.Parameters.AddWithValue("@ApproxUnitPrice", TextBox16.Text);
cmd2.ExecuteNonQuery();
}
else if (MultiView1.ActiveViewIndex == 2)
{
if (FileUpload1.HasFile)
{
byte[] productImage = FileUpload1.FileBytes;
String insertstring2 = @"Insert INTO Cert (CertName, CertLogo)
values(@CertName, @CertLogo)";
SqlCommand cmd3 = new SqlCommand("insertstring2", conn);
cmd3.CommandText = insertstring2;
cmd3.CommandType = CommandType.Text;
cmd3.Parameters.AddWithValue("@CertName", TextBox18.Text);
cmd3.Parameters.Add("@CertLogo", SqlDbType.VarBinary).Value = productImage;
cmd3.ExecuteNonQuery();
}
}
}
catch (System.Data.SqlClient.SqlException ex)
{
string msg = "Insert Error:";
msg += ex.Message;
throw new Exception(msg);
}
finally
{
Session.Abandon();
conn.Close();
}
}
protected void Button1_Click(object sender, EventArgs e)
{
InsertInfo();
MultiView1.ActiveViewIndex += 1;
}
protected void Button2_Click(object sender, EventArgs e)
{
MultiView1.ActiveViewIndex -= 1;
}
protected void Button5_Click(object sender, EventArgs e)
{
Response.Write("Successful");
}
}
}
我無法添加代碼，它說ident 4空間，我不明白。所以我發佈了我在論壇asp中發佈問題的鏈接。感謝， – Girish 2012-07-19 06:47:44
當您編輯帖子時，只需選擇代碼並單擊工具欄上的{_} _按鈕{ – Jupaol 2012-07-19 06:50:55
好吧，謝謝，我發佈了我的代碼..請檢查.. :) – Girish 2012-07-19 06:52:41