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我想要插入數據字段,如:id = 1,id_page = 12356。我讀了id_page
出一個html文件和我總是收到此錯誤信息:
警告:請求mysql_query()預計參數1爲字符串,資源 在 的/ mnt/webi/B0 /53443744分之44給出/htdocs/digitalpiano-test/kitareader.php上 14行錯誤
<?php
$con = mysql_connect("rdbms.strato.de","U1363575","asdasd123","DB1363575");
if (mysqli_connect_errno())echo "Failed to connect to MySQL: " . mysqli_connect_error();
$name = file_get_contents('kitas.html'); $array_name = explode("<tr>", $name);
foreach($array_name as $value) {
$value2 = explode('<a href="kitaDetails.aspx?ID=',$value);
$value3 = explode('">',$value2[1]);
$id_page = $value3[0];
$eintragen = mysql_query($con,"INSERT INTO kita_berlin (id_page) VALUES ('$id_page')") or die ("error");
} ?>
有什麼不對?
嗯我仍然收到錯誤:/ – Susanne92
什麼是錯誤? – Achrome
我得到錯誤信息或死('錯誤') – Susanne92