不能丟棄熊貓列

Question

我有一個熊貓數據框，我需要根據數值切分成幾個表格並保存到多個.csv文件中。這個方法似乎可行，但是它創建了一個我不能放下的列（第一個）（而不是第二列）。有人能告訴我爲什麼它在那裏，我該如何擺脫它？謝謝。下面是代碼：

new_d['Supplier'] = new_d.apply(lambda row: determine_supplier(row), axis = 1) 
new_d.sort_values(by = ['Supplier'], inplace = True) 
new_d.set_index(keys = ['Supplier'], drop = False, inplace = True) 
suppliers = new_d['Supplier'].unique().tolist() 
for supplier in suppliers: 
    po = new_d.loc[new_d.Supplier == supplier] #the problem is here? 
    po = po.drop(po.columns[[0]], axis = 1) # can't drop 
    po.to_csv(path_or_buf = r'PO\\' + supplier + '_PO.csv') 

Answer 1

在DataFrame一列稱爲index。

您需要to_csv參數index=False的忽略它：

po.to_csv(path_or_buf = r'PO\\'+ supplier+'_PO.csv',index=False) 

或者更好：

相反：

for supplier in suppliers: 
    po = new_d.loc[new_d.Supplier == supplier] #the problem is here? 
    po = po.drop(po.columns[[0]], axis = 1) # can't drop 
    po.to_csv(path_or_buf = r'PO\\' + supplier + '_PO.csv') 

使用groupby爲looping：

for supplier, po in new_d.groupby('Supplier'): 
    po.to_csv(r'PO\\'+ supplier +'_PO.csv',index=False)